如何在Java中解析這種類型的JSON？

Question

我該如何從leaveInfo獲取第三個leaveTypeId和年份？

{  
"statusCode":"1001",
"message":"Success",
"response":{  
  "leaveInfo":[  
     {  

        "leaveTypeId":1,
        "year":2014

     },
     {  

        "leaveTypeId":2,
        "year":2014

     },
     {  
        "leaveTypeId":3,
        "year":2014,

     },
     {  
        "leaveTypeId":4,
        "year":2014
     },
     {  
        "leaveTypeId":5,
        "year":2014
     },
     {  
        "leaveTypeId":6,
        "year":2014
     }
  ]
}
}

我這樣做是為了滿足我的需要

JSONObject jobj1 = new JSONObject(result);
String statusCode = jobj1.getString("statusCode");
if (statusCode.equalsIgnoreCase("1001"))
{
    String response = jobj1.getString("response");
    JSONObject jobj2 = new JSONObject(response);
    String leaveInfo = jobj2.getString("leaveInfo");
    System.out.println("leaveInfo: "+leaveInfo);
}

我不知道該怎么做，因為在leaveInfo中沒有數組的鍵值。 請在這方面幫助我。

Answer 1

用這個

JSONObject jobj1 = new JSONObject(result);
String statusCode = jobj1.getString("statusCode");
if (statusCode.equalsIgnoreCase("1001"))
{
 String response = jobj1.getString("response");
 JSONObject jobj2 = new JSONObject(response);
 JSONArray ary=jobj2.getJSONArray("leaveInfo");
 for(int i=0;i<ary.length;i++){
 JSONObject obj=ary.getJSONObject(i);
 String leaveInfo=obj.getString("leaveTypeId");
 System.out.println("leaveInfo: "+leaveInfo);
 } 

 }

希望對您有幫助：)