簡體   English   中英

SQL查詢根據交易日期加入數據以獲取本月和上個月的費用

[英]SQL query to join data based on transaction date to get this month's & previous month's cost

我有一個交易數據集,其中包含諸如product_id,cost_unit,date等列。產品的成本逐月變化。 我想要一個具有以下結構的表

Product | Cost_from_this_Month | Cost_from_Previous_month

每個月一個產品可以有多行,但是該月的成本是相同的。 即,費用固定為一個月。 如何構造查詢以獲得所需的結果?

我知道如何獲取最新費用:

  SELECT * FROM (
  SELECT Product, Cost_Unit
                    , Date
                        , zrank = row_number() OVER ( PARTITION BY Product ORDER BY Date DESC)
                FROM    MY_Table
            ) a where a.zrank = 1

誰能幫我?

如果您使用的是SQL Server 2012或更高版本,條件聚合和lag()函數如何?

select year(date), month(date), max(cost_unit) as thismonthcost,
       lag(max(cost_unit)) over (order by year(date), month(date)) as lastmonthcost
from my_table
group by year(date), month(date)

如果您使用的是SQL Server 2012或更高版本,則可以使用LEADLAG

DECLARE @Products TABLE (
    Product VARCHAR(100),
    Cost_Unit MONEY,
    [Date] DATETIME
)
INSERT @Products VALUES
    ('Widget', 10, '1/1/2014'),
    ('Widget', 12, '2/1/2014'),
    ('Widget', 15, '3/1/2014'),
    ('Widget', 17, '4/1/2014'),
    ('Gizmo', 20, '1/1/2014'),
    ('Gizmo', 25, '2/1/2014'),
    ('Gizmo', 26, '3/1/2014'),
    ('Gizmo', 27, '4/1/2014')

SELECT
    Product,
    [Date],
    Products.Cost_Unit AS [Cost_This_Month],
    LAG(Products.Cost_Unit) OVER (PARTITION BY Product ORDER BY [Date]) AS [Cost_Last_Month]
FROM @Products Products
ORDER BY Product, [Date] DESC

這里的輸出產生:

Product         Date                    Cost_This_Month       Cost_Last_Month
--------------- ----------------------- --------------------- ---------------------
Gizmo           2014-04-01 00:00:00.000 27.00                 26.00
Gizmo           2014-03-01 00:00:00.000 26.00                 25.00
Gizmo           2014-02-01 00:00:00.000 25.00                 20.00
Gizmo           2014-01-01 00:00:00.000 20.00                 NULL
Widget          2014-04-01 00:00:00.000 17.00                 15.00
Widget          2014-03-01 00:00:00.000 15.00                 12.00
Widget          2014-02-01 00:00:00.000 12.00                 10.00
Widget          2014-01-01 00:00:00.000 10.00                 NULL

如果您未使用SQL 2012或更高版本,並且無法使用這些新功能,則CROW ROW_NUMBER還將為您提供以下功能:

;WITH CTE AS (
    SELECT
        Product,
        [Date],
        Cost_Unit,
        ROW_NUMBER() OVER (PARTITION BY Product ORDER BY [Date] DESC) AS RowNum
    FROM @Products
)
    SELECT
        CM.Product,
        CM.Product,
        CM.Cost_Unit AS [Cost_This_Month],
        LM.Cost_Unit AS [Cost_Last_Month]
    FROM CTE CM
        LEFT OUTER JOIN CTE LM
            ON CM.Product = LM.Product
                AND CM.RowNum = LM.RowNum - 1

更新更新以考慮一個月中的多個事務。 假設該月的最后一筆交易是您當月使用的費用(例如,如果5/1上為$ 10,5 / 5上為$ 11,則May的Cost_Unit為$ 11)。

-- LAG Solution
SELECT
    Product,
    [Date],
    Products.Cost_Unit AS [Cost_This_Month],
    LAG(Products.Cost_Unit) OVER (
        PARTITION BY Product ORDER BY [Date]) AS [Cost_Last_Month]
FROM (
    SELECT *, ROW_NUMBER() OVER (
        PARTITION BY Product, YEAR([Date]), MONTH([Date])
        ORDER BY [Date] DESC) AS RowNum
    FROM @Products
    ) Products
WHERE RowNum = 1
ORDER BY Product, [Date] DESC

-- ROW_NUMBER() Solution
;WITH CTE AS (
    SELECT
        Product,
        [Date],
        Cost_Unit,
        ROW_NUMBER() OVER (PARTITION BY Product ORDER BY [Date] DESC) AS RowNum
    FROM (
        SELECT *, ROW_NUMBER() OVER (
            PARTITION BY Product, YEAR([Date]), MONTH([Date])
            ORDER BY [Date] DESC) AS RowNum
        FROM @Products
        ) Products
    WHERE Products.RowNum = 1
)
    SELECT
        CM.Product,
        CM.[Date],
        CM.Cost_Unit AS [Cost_This_Month],
        LM.Cost_Unit AS [Cost_Last_Month]
    FROM CTE CM
        LEFT OUTER JOIN CTE LM
            ON CM.Product = LM.Product
                AND CM.RowNum = LM.RowNum - 1

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM