JavaScript：關聯/對象數組中的indexOf？

Question

我有這個數組：

var skins = {};
skins.w = "http://example.com/public/images/char_elements/base.png";

var eyes = {};
eyes.b = "http://example.com/public/images/char_elements/eyes/blue.png";
eyes.g = "http://example.com/public/images/char_elements/eyes/green.png";
eyes.r = "http://example.com/public/images/char_elements/eyes/red.png";

var hair = {};
hair.b = "http://example.com/public/images/char_elements/hair/black.png";
hair.w = "http://example.com/public/images/char_elements/hair/blond.png";
hair.s = "http://example.com/public/images/char_elements/hair/brown.png";

var mouth = {};
mouth.h = "http://example.com/public/images/char_elements/mouth/happy.png";

var pants = {};
pants.s = "http://example.com/public/images/char_elements/pants/shorts.png";

var shoes = {};
shoes.b = "http://example.com/public/images/char_elements/shoes/black.png";

var torso = {};
torso.s = "http://example.com/public/images/char_elements/torso/shirt.png";

而這個功能：

function SwitchElement(type){
switch(type){

    case "eyes":
    var cur = eyes.indexOf(document.getElementById(type).src);
    console.log(cur);
//  var eyesId = document.getElementById("
    break;
}
}

所有這一切都被稱為：

<img class="builder_control_front" src="http://claro.mib.infn.it/arrow.png" onclick="SwitchElement('eyes');"/>

所以基本上當用戶點擊箭頭時，它會調用javascript函數來獲取當前圖像，獲取元素所在的數組索引（在本例中為數組：“eyes”）並循環遍歷它。

我需要通過url獲取索引，當我嘗試使用indexOf它拋出未定義時，我讀到如果數組已命名索引，JavaScript將把數組轉換為Object。

那么我能獲得當前加載圖像的索引嗎？

注意：我需要有以下代碼的數組：b，g，r，w，w4，b3等。所以更改為普通數組不是一個選項，或許更改為多維數組會更好？

Answer 1

為什么不迭代你的對象並找到包含值的鍵：

function findKey(obj, value) {
    for (var key in obj) {
        if (obj[key] == value) return key
    }
    return null;
}

var key = findKey(eyes, document.getElementById(type).src);
if (key != null) { 

} else {

}

Answer 2

你需要的是反向查找。 假設您的所有網址都是唯一的，您可以創建一個這樣的網址：

function invert(obj) {
    var newObj = {};
    for(var key in obj) {
        if (obj.hasOwnProperty(key)) {
            newObj[obj[key]] = key;
        }
    }
}

var hair = {};
hair.b = "http://example.com/public/images/char_elements/hair/black.png";
hair.w = "http://example.com/public/images/char_elements/hair/blond.png";
hair.s = "http://example.com/public/images/char_elements/hair/brown.png";
var hairReverse = invert(hair);

var url = "http://example.com/public/images/char_elements/hair/black.png";
console.log(hairReverse[url]); // logs "b"

如果你正在使用Lodash / Underscore，它有一個內置的反轉功能 ：

var hairReverse = _.invert(hair);