從表單輸入數據到Database PDO

Question

我學習了MySQL，創建了一個表單並讓它與數據庫一起工作。 然后我被告知我應該用准備好的語句來做PDO，所以我做了一些研究並改變了我的代碼。

我現在有正確的代碼（我認為），但我無法弄清楚數據是如何輸入的。 正如您在我的代碼中看到的那樣，我讓數據庫在用戶提交表單時創建行。 但是，數據庫只會在//insert a row和//insert another row的語音標記內找到任何內容。

例如，現在如果用戶完成並提交表單，無論他們輸入什么信息，我只會在我的數據庫中顯示“Joe”和“joe@example.com”等。 顯然我需要他們的答案，否則我的表格將是無關緊要的（數據提交也是如此）。 我完全錯過了這個標記還是我錯過了一些愚蠢的東西？ 我嘗試過改變和研究，但我正在努力。 對這一切真的很新。

形成：

<form action="testsubmit-pdo.php" method="post">
<label>Student Name :</label>
<input type="text" name="stu_name" id="name" required="required"       placeholder="Please Enter Name"/><br /><br />
<label>Student Email :</label>
<input type="email" name="stu_email" id="email" required="required" placeholder="john123@gmail.com"/><br/><br />
<label>Student City :</label>
<input type="text" name="stu_city" id="city" required="required" placeholder="Please Enter Your City"/><br/><br />
<input type="submit" value=" Submit " name="submit"/><br />
</form>

PHP：

try {
$conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);

// set the PDO error mode to exception
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

// prepare sql and bind parameters
$stmt = $conn->prepare("INSERT INTO demo (stu_name, stu_email, stu_city)
VALUES (:stu_name, :stu_email, :stu_city)");
$stmt->bindParam(':stu_name', $stu_name);
$stmt->bindParam(':stu_email', $stu_email);
$stmt->bindParam(':stu_city', $stu_city);

// insert a row
$stu_name = "Joe";
$stu_email = "joe@example.com";
$stu_city = "Joeland";
$stmt->execute();

// insert another row
$stu_name = "Mary";
$stu_email = "mary@example.com";
$stu_city = "Maryland";
$stmt->execute();

echo "New records created successfully";
}
catch(PDOException $e)
{
echo "Error: " . $e->getMessage();
}
$conn = null;

Answer 1

改變這個 -

// insert a row
$stu_name = "Joe";
$stu_email = "joe@example.com";
$stu_city = "Joeland";
$stmt->execute();

// insert another row
$stu_name = "Mary";
$stu_email = "mary@example.com";
$stu_city = "Maryland";
$stmt->execute();

對此 -

// insert a row
$stu_name = $_POST['stu_name'];
$stu_email = $_POST['stu_email'];
$stu_city = $_POST['stu_city'];
$stmt->execute();

您的表單將把值放在PHP的POST數組中，您可以通過表單中的name屬性訪問它們。

Answer 2

您將用戶輸入的數據發布到您的php文件

<form action="some_php_file.php" method="post">
  <input type="text" name="stu_name">
   <input type="email" name="stu_email">
  <input type="text" name="stu_city">
  <input type="submit" name="submit" value="submit">
</form>

在PHP代碼中，首先需要檢查是否單擊了提交按鈕

   //check if submit button is clicked
  If(isset($_POST['submit'])){
    try {
    $conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);

  // set the PDO error mode to exception
   $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

   // prepare sql and bind parameters
   $stmt = $conn->prepare("INSERT INTO demo (stu_name, stu_email, stu_city)
    VALUES (:stu_name, :stu_email, :stu_city)");
    $stmt->bindParam(':stu_name', $stu_name);
   $stmt->bindParam(':stu_email', $stu_email);
   $stmt->bindParam(':stu_city', $stu_city);

    $stu_name = $_POST['stu_name'];
    $stu_email = $_POST['stu_email'];
    $stu_city = $_POST['stu_city'];
    $stmt->execute();
    echo "New records created successfully";
}catch(PDOException $e){
  echo "Error: " . $e->getMessage();
}
$conn = null;
}