無法從Android中的JSON將數據獲取到PHP Web服務

Question

    import android.app.Activity;
    import android.os.Bundle;
    import android.os.StrictMode;
    import android.util.Log;
    import android.view.View;
    import android.widget.Button;
    import android.widget.EditText;
    import android.widget.Toast;

    import org.apache.http.HttpResponse;
    import org.apache.http.client.methods.HttpPost;
    import org.apache.http.entity.StringEntity;
    import org.apache.http.impl.client.DefaultHttpClient;
    import org.apache.http.message.BasicHeader;
    import org.apache.http.protocol.HTTP;
    import org.apache.http.util.EntityUtils;
    import org.json.JSONObject;


    public class MainActivity extends Activity {

        @Override
        protected void onCreate(Bundle savedInstanceState) {
            super.onCreate(savedInstanceState);
            setContentView(R.layout.activity_main);

            if (android.os.Build.VERSION.SDK_INT > 9) {
                StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
                StrictMode.setThreadPolicy(policy);
            }

            Button btn = (Button) findViewById(R.id.btnInsert);
            EditText editText = (EditText) findViewById(R.id.editText);

            final String value = editText.getText().toString();

            btn.setOnClickListener(new View.OnClickListener() {
                @Override
                public void onClick(View v) {

                    try {
                        JSONObject jsonobj = new JSONObject();
                        jsonobj.put("name", value);

                        DefaultHttpClient httpclient = new DefaultHttpClient();
                        HttpPost httppostreq = new HttpPost("http://www.myurl.com/WebserviceInsert2.php");

                        StringEntity se = new StringEntity(jsonobj.toString());

                        Log.d("jsonobj is :>", String.valueOf(jsonobj));

                        se.setContentType("application/json;charset=UTF-8");
                        se.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE, "application/json;charset=UTF-8"));

                        httppostreq.setEntity(se);

                        HttpResponse httpresponse = httpclient.execute(httppostreq);

                        String responseText = null;
                        try {
                            responseText = EntityUtils.toString(httpresponse.getEntity());   // {"code":1}
                        } catch (Exception e) {
                            e.printStackTrace();
                            Log.i("Parse Exception", e + "");
                        }

                        Log.d("Response Text is : ", responseText);

                        JSONObject json = new JSONObject(responseText);

                        int code = json.getInt("code");

                        if (code == 1)
                            Toast.makeText(getApplicationContext(), "Successful", Toast.LENGTH_LONG).show();
                        else
                            Toast.makeText(getApplicationContext(), "Fail", Toast.LENGTH_LONG).show();
                    } catch (Exception e) {
                        Log.d("Error :>", String.valueOf(e));
                    }
                }
            });
        }
    }



PHP Code:
<?php

    include("include/config.php"); 

    $name=$_POST["name"];
    //echo $name;

    $flag['code']=0;

    if($result=mysql_query("INSERT INTO test (name) VALUES ('".$name."')")) 
    {
        $flag['code']=1;
    }

    print(json_encode($flag));

    $obj->close();

?>

數據庫表字段“名稱”為空。 插入查詢成功觸發，但是..數據未插入表中。

我認為PHP文件沒有從android applicaiton（JSON）發送的POST方法中正確獲取“ name”參數。

Answer 1

您尚未發布實際的logcat，但可以嘗試以下代碼

HttpClient httpClient = new DefaultHttpClient();
//Get COding
HttpPost httpPost = new HttpPost(your_url);
List<NameValuePair> parameters = new ArrayList<NameValuePair>();
parameters.add(new BasicNameValuePair("name", value));
//you can add  more parameters here
httpPost.setEntity(new UrlEncodedFormEntity(parameters));
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
response=EntityUtils.toString(httpEntity);

您可以添加或設置內容類型或“常規標題”，以了解更多信息http://developer.android.com/reference/org/apache/http/client/HttpClient.html

Answer 2

因為您使用GET，Method來請求該網址。 如果您向服務器發送任何請求而沒有提及，則HttpClient將假定該請求為GET，但是在您的PHP中，您提及了它的$ _POST [“ name”]; 如果替換= $ _ POST [“ name”]; 與_REQUEST [“ name”];

否則，您必須將請求類型設置為Post。

然后數據可能會插入到數據庫中。