[英]Prepared statement in PHP
我正在嘗試准備/綁定此語句,但是它失敗了,並且沒有產生錯誤,因此我在如何繼續上苦苦掙扎。
prepare()
調用失敗,並返回bool(false)。
// establish connection
$conn = new mysqli(###, ###, ###, ###);
// here are the record values
$dt = date('Y-m-d H:i:s', time());
$record_vals = array(
'ticket_id' => 'val',
'requester_name' => 'val',
'domain' => 'val',
'created_at' => $dt,
'updated_at' => $dt
);
// insert or update the record
try
{
$stmt = $conn->prepare("
INSERT INTO tickets
(ticket_id,requester_name,domain,created_at,updated_at)
VALUES
(:ticket_id,:requester_name,:domain,:created_at,:updated_at)
ON DUPLICATE KEY UPDATE
requester_name=:requester_name,domain=:domain,updated_at=:updated_at
");
foreach ($record_vals as $key => $value)
{
$stmt->bindParam(':'.$key, $value);
}
$stmt->execute();
}
catch(PDOException $e)
{
echo "Error: " . $e->getMessage();die();
}
您似乎在混用兩個不同的PHP函數。 mysqli
和PDO
。
編輯:這是一種方法。
PDO
$host = "host";
$username = "username";
$password = "password";
$database = "db";
try {
// Connection setup
$pdo = new PDO("mysql:host=$host;dbname=$database", $username, $password);
$query = $pdo->prepare($sql_query); //Replace $sql_query with SQL statement
$query->execute();
while($rows = $query->fetch()) {
$array = $rows; //Store info in an array
}
} catch (PDOException $PDOException) {
// Get connection errors and exit the script
print($PDOException->getMessage());
exit();
}
有關更多信息,我會說去閱讀手冊 。
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