HTML / PHP表單選擇帶有MySQL鏈接的選項

Question

我在這里按照上一個問題得到一個鏈接到MySQL的下拉菜單。 它的工作方式沒有表格，只有表格，所有的room_id只是散布在一條線上而不是放在下拉框中。 關於如何修復它的任何想法？ 謝謝

//Creates a form for room_id
echo "<form action=''>";
echo "<select name='room_id'>";
//Creates drop down box to show the current rooms vacant
$sql = "SELECT * FROM room";
$sql.= " WHERE room_vacant = 1";
$stmt = $dbh->query($sql);
echo "<select name='room_id'>";
while($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
    echo "<option value='" . $row['room_id'] . "'>" . $row['room_id'] . "</option>";
} //Closes drop down box
echo "</select>";

//Submit button
echo "<input type='submit' value='Submit'>";

//Closes form
echo "</form>";

Answer 1

原因是你回復你的選擇兩次。 刪除一個。

//Creates a form for room_id
echo "<form action=''>";
echo "<select name='room_id'>";
//Creates drop down box to show the current rooms vacant
$sql = "SELECT * FROM room";
$sql.= " WHERE room_vacant = 1";
$stmt = $dbh->query($sql);
while($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
    echo "<option value='" . $row['room_id'] . "'>" . $row['room_id'] . "</option>";
} //Closes drop down box
echo "</select>";

//Submit button
echo "<input type='submit' value='Submit'>";

//Closes form
echo "</form>";