將值插入現有值MySQL

Question

可以說我有這張桌子。

 ID  Message

 1   Jack went to the park.
 2   Jamie went to the store.
 3   Lucy finished school.

如何在不完全覆蓋現有值的情況下將值大量插入到“ Message列中？

例如

 ID  Message

 1   Jack went to the park **at 3pm**.
 2   Jamie went to the store **at 3pm**.
 3   Lucy finished school **at 3pm**.

我知道我可以通過PHP來實現此目的，方法是檢索值，然后通過數組/循環將其與其他值重新插入，但我希望僅通過PhpMyAdmin與MySQL一起完成此操作。

Answer 1

UPDATE `table`
   SET `Message` = CONCAT(`Message`, " at 3pm")
 WHERE 1;