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[英]How to create a dynamic dropdown list in codeigniter using mysql database table
[英]How to save dynamic generated table data to mysql database in php codeigniter
我在PHP代碼點火器中創建了一個Web應用程序,它生成包含員工收入,扣除計算的表。 因為我是CI的新手。 我試圖將動態生成的表數據保存到數據庫,但失敗了。 我沒有得到如何將表數據POST到Controller。 歡迎任何幫助。
function index()
{
if($this->input->post("submit"))
{
$vals=$this->cpanel_model->esic();
if($vals){
$data['w_share']=$vals->w_share;
$data['e_share']=$vals->e_share;
}
$data["wshare"]="";
//echo $data['w_share'];
$city=$_POST["city"];
$v1= $data['w_share'];
$v2= '100';
$v3= $data['e_share'];
$arr=$_POST["wid"];
$arr1=$_POST["days"];
$arr2=$_POST["payment"];
$arr3=$_POST["wdays"];
for ($i=0; $i <count($arr1) ; $i++)
{
$net[$i]=($arr2[$i]/$arr3[$i])*$arr1[$i];
$wshare[$i]=($net[$i]/$v2)*$v1;
$eshare[$i]=($net[$i]/$v2)*$v3;
$total[$i]=$eshare[$i]+$wshare[$i];
$wdays[$i]=$arr3;
$days[$i]=$arr1;
}
$data["net"]=$net;
$data["wshare"]=$wshare;
$data["total"]=$total;
$data["eshare"]=$eshare;
$data["wdays"]=$arr3;
$data["days"]=$arr1;
$data["list"]=$this->payment_model->search($city);
$this->load->view("secure/php-version/esic",$data);
}
<?php echo form_open('esic/insert',array("role"=>"form")); ?>
<div class="table-responsive">
<table border="1" id="t01" class="table table-striped table-bordered table-hover table-condensed">
<tr>
<th>Worker_id</th>
<th>Worker Name</th>
<th>Worker City</th>
<th>Designation</th>
<th>Working Days</th>
<th>Basic Payment</th>
<th>Net Payment</th>
<th>Present Days</th>
<th>Worker Share (1.75%)</th>
<th>Employee Share (4.75%)</th>
<th>Total</th>
</tr>
<?php $i=0; $sum2=0; ?>
<?php if(count($list)>0) { foreach ($list as $std) {?>
<tr>
<?php echo form_hidden("wid[]",$std["wid"]); ?>
<?php echo form_hidden("wdays[]",$wdays); ?>
<?php echo form_hidden("payment[]",$std["payment"]); ?>
<td><?php echo $std["wid"]; ?></td>
<td><?php echo $std["wname"]; ?></td>
<td><?php echo $std["city"]; ?></td>
<td><?php echo $std["designation"]; ?></td>
<td><?php echo $wdays[$i]; ?></td>
<td><?php echo $std["payment"]; ?></td>
<td><?php echo $net[$i]; ?></td>
<td><?php echo $days[$i]; ?></td>
<td><?php echo $wshare[$i]; ?></td>
<td><?php echo $eshare[$i]; ?></td>
<td><?php echo $total[$i]; ?></td>
<?php $sum2 += $std["payment"]; ?>
</tr>
<?php $i++;}}?>
<tr>
<?php
$sum=0;
$sum1=0;
$sum3=0;
$sum4=0;
$sum5=0;
$i=0;
foreach ($total as $value) {
$sum = $sum + $value;
$i++;
}
foreach ($days as $value) {
$sum1 = $sum1 + $value;
$i++;
}
foreach ($eshare as $value) {
$sum3 = $sum3 + $value;
$i++;
}
foreach ($wshare as $value) {
$sum4 = $sum4 + $value;
$i++;
}
foreach ($net as $value) {
$sum5 = $sum5 + $value;
$i++;
}
?>
<td>
</td>
<td>
</td>
<td>
</td>
<td>
</td>
<td>
</td>
<td style="font-weight:bold; font-size:10pt;">
<?php echo $sum2; ?>
</td>
<td style="font-weight:bold; font-size:10pt;">
<?php echo $sum5; ?>
</td>
<td style="font-weight:bold; font-size:10pt;">
<?php echo $sum1; ?>
</td>
<td style="font-weight:bold; font-size:10pt;">
<?php echo $sum4; ?>
</td>
<td style="font-weight:bold; font-size:10pt;">
<?php echo $sum3; ?>
</td>
<td style="font-weight:bold; font-size:10pt;">
<?php echo $sum; ?>
</td>
</tr>
</table>
</div>
<?php echo form_submit(array("name"=>"submit","type"=>"submit","value"=>"Create ESIC")); ?>
<?php echo form_close(); ?>
它不太清楚你當前如何生成表格,但無論如何,當你生成表格時,你必須將它放在一個表格中,並為輸入分配鍵。 試試這種方法:
HTML(這些是生成表時應該得到的結果)
<form action="<?= base_url() ?>table_data" method="post">
<table>
<thead>
<tr>
<th>Name</th>
<th>Earnings</th>
<th>Deduction</th>
</tr>
</thead>
<tbody>
<tr>
<td><input type="hidden" name="table[0][name]" value="name1">name1</td>
<td><input type="hidden" name="table[0][earning]" value="earning1">earning1</td>
<td><input type="hidden" name="table[0][deduc]" value="deduc1">deduc1</td>
</tr>
<tr>
<td><input type="hidden" name="table[1][name]" value="name1">name1</td>
<td><input type="hidden" name="table[1][earning]" value="earning1">earning1</td>
<td><input type="hidden" name="table[1][deduc]" value="deduc1">deduc1</td>
</tr>
</tbody>
</table>
<input type="submit" value="Submit this table">
</form>
控制器:
function table_data() {
if ($this->input->post()) {
$table_data = $this->input->post('table');
$this->load->model('model_name');
$this->model_name->insert_table_data($table_data);
}
}
模型:
function insert_table_data($table_data){
$this->db->insert_batch('mytable', $table_data);
}
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