為什么HashMap方法返回空對象引用？

Question

我試圖制作一個HashMap方法來獲取SQLite數據庫數據，但是當我調用該方法時，它返回的null引用使我的Android應用程序停止工作。

這是我的代碼：

HashMap方法：

public HashMap<String, String> getUserDetails(){
    HashMap<String,String> user = new HashMap<String,String>();
    String selectQuery = "SELECT  * FROM " + TABLE_LOGIN;

    SQLiteDatabase db = this.getReadableDatabase();
    Cursor cursor = db.rawQuery(selectQuery, null);

    cursor.moveToFirst();
    if(cursor.getCount() > 0){
        user.put("name", cursor.getString(1));
        user.put("position", cursor.getString(2));
        user.put("level", cursor.getString(3));
        user.put("email", cursor.getString(4));
        user.put("uid", cursor.getString(5));
        user.put("created_at", cursor.getString(6));
    }
    cursor.close();
    db.close();

    return user;
}

這就是我如何在其他類中調用方法

DatabaseHandler db = new DatabaseHandler(getApplicationContext());
HashMap<String,String> userDetail= db.getUserDetails();
int userLevel = Integer.parseInt(userDetail.get("level").toString());

無論如何，我使用教程參考來做到這一點並與我自己的需求融合。

Answer 1

如果用戶存在於數據庫中，則應返回user對象，否則返回null並檢查該user是否為null

public HashMap<String, String> getUserDetails(){
    HashMap<String,String> user = null;
    String selectQuery = "SELECT  * FROM " + TABLE_LOGIN;

    try {
    SQLiteDatabase db = this.getReadableDatabase();
    Cursor cursor = db.rawQuery(selectQuery, null);

    if (cursor != null){
    cursor.moveToFirst();
    if(cursor.getCount() > 0){
        user = new HashMap<String,String>();
        user.put("name", cursor.getString(1));
        user.put("position", cursor.getString(2));
        user.put("level", cursor.getString(3));
        user.put("email", cursor.getString(4));
        user.put("uid", cursor.getString(5));
        user.put("created_at", cursor.getString(6));
    }
}
} finally {
    cursor.close();
    db.close();
}

    return user;
}

然后

DatabaseHandler db = new DatabaseHandler(getApplicationContext());
HashMap<String,String> userDetail= db.getUserDetails();
if (userDetail != null) {
  String level = userDetail.get("level");
  if (level != null){
    try {
      int userLevel = Integer.parseInt(level);
    } catch (Exception e){
     e.printStackTrace();
    }
  }
}