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[英]How to access nested resource parameters from parent controller in Ruby on Rails?
[英]How to access 'layout' of parent controller?
在我的一個控制器中,我希望在給定某些條件的情況下更改布局,否則保持父ApplicationController使用的默認布局(最初是“應用程序”,但我現在正嘗試其他一些)。 嘗試使用alias_method訪問“布局”,但它似乎不起作用。 我的代碼:
class SomeController < ApplicationController
alias_method :parent_layout, :layout
layout :some_layout
def some_layout
if some_condition
"new_layout"
else
:parent_layout
end
end
end
這給出了一個錯誤:
ActionController::RoutingError (undefined method `layout' for class `SomeController'):
app/controllers/some_controller.rb:6:in `alias_method'
app/controllers/some_controller.rb:6:in `<class:SomeController>'
app/controllers/some_controller.rb:3:in `<top (required)>'
看起來你有很多選擇。 查看這里的文檔(搜索“查找布局”) http://guides.rubyonrails.org/layouts_and_rendering.html
一些可能性,取決於您需要它的復雜程度:
# Proc-based
class ProductsController < ApplicationController
layout Proc.new { |controller| controller.request.xhr? ? "popup" : "application" }
end
# Route based, :except and :only
class ProductsController < ApplicationController
layout "product", except: [:index, :rss]
end
# Method-based
class OldArticlesController < SpecialArticlesController
layout false
def show
@article = Article.find(params[:id])
end
def index
@old_articles = Article.older
render layout: "old"
end
# ...
end
我不確定你的代碼是如何構建的,但它看起來像第一個可能對你有用:
class SomeController < ApplicationController
layout Proc.new { |controller| controller.some_condition? ? "new_layout" : "application" }
end
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