[英]MySQL Product filters by multiple attributes
如何獲得具有所有要求屬性的產品
SELECT * FROM `oc_product_attribute` WHERE (`attribute_id`=15 AND `text`="2500") OR (`attribute_id`=18 AND `text`="24")
此請求,返回以下結果:
|product_id | attribute_id | language_id | text
+-----------+--------------+-------------+-----
|1 | 15 | 1 | 2500
|2 | 15 | 1 | 2500
|3 | 15 | 1 | 2500
|4 | 15 | 1 | 2500
|3 | 18 | 1 | 24
|4 | 18 | 1 | 24
但我只需要乘積3和4,因為它們的乘積為15 = 2500和18 = 24。 我該怎么做?
如果要匹配多個條件並返回匹配所有條件的值,則可以使用此方法
select p1.* from oc_product_attribute p1
where
p1.`attribute_id`=15 AND p1.`text`='2500'
and exists
(
select 1 from oc_product_attribute p2
where
p2.attribute_id = 18
and p2.text = 24
and p1.product_id = p2.product_id
)
union all
select p1.* from oc_product_attribute p1
where
p1.`attribute_id`=18 AND p1.`text`='24'
and exists
(
select 1 from oc_product_attribute p2
where
p2.attribute_id = 15
and p2.text = 2500
and p1.product_id = p2.product_id
)
;
SELECT product_id
FROM oc_product_attribute
WHERE (attribute_id,text) IN ((15,'2500'),(18,'24'))
GROUP
BY product_id
HAVING COUNT(DISTINCT attribute_id,text) = 2;
我覺得這個速記法否定了索引的使用,但希望您能理解。
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.