遍歷對象並過濾給定屬性javascript中的給定特定值

Question

我在網上看過，無法找到關於我所遇到問題的詳細答案。 我有一個看起來像這樣的對象：

 {
"00001": {
    "sid": "00001",
    "oid": "00001",
    "name": "operation 0001 service 1",
    "description": "test operation 000001",
    "returntype": "something",
    "parameters": {
        "00001": {
            "pid": "00001",
            "name": "parameter 00001 operation 0001 service 1",
            "description": "test parameter 000001",
            "type": "something"
        }
    }
},
"00002": {
    "sid": "00002",
    "oid": "00002",
    "name": "operation 0001 service 2",
    "description": "test operation 000001",
    "returntype": "something",
    "parameters": {}
},
"00003": {
    "sid": "00003",
    "oid": "00003",
    "name": "operation 0001 service 3",
    "description": "test operation 000001",
    "returntype": "something",
    "parameters": {}
},
"00004": {
    "sid": "00004",
    "oid": "00004",
    "name": "operation 0001 service 4",
    "description": "test operation 000001",
    "returntype": "something",
    "parameters": {}
},
"00005": {
    "sid": "00005",
    "oid": "00005",
    "name": "operation 0001 service 5",
    "description": "test operation 000001",
    "returntype": "something",
    "parameters": {}
},
"00006": {
    "sid": "00001",
    "oid": "00006",
    "name": "operation 0001 service 6",
    "description": "test operation 000001",
    "returntype": "something",
    "parameters": {}
}
}

我正在嘗試遍歷對象，並能夠返回那些具有特定sid（即00001）的對象，我在javascript中知道在obj中有一個for var，但是我不確定如何實現它以便獲取所需的輸出。 任何幫助或指導將不勝感激。

Answer 1

如果您知道這僅是一個級別的深度（“ sid”匹配項只會在對象的第一級別找到，並且您也不在搜索嵌套的對象），那么它會更加直接：

function findMatches(data, prop, val) {
    var item, matches = [];
    for (var obj in data) {
        item = data[obj];
        if (item[prop] === val) {
            matches.push(item);
        }
    }
    return matches;
}

var result = findMatches(myData, "sid", "00001");

工作演示： http : //jsfiddle.net/jfriend00/s5xg1khy/

Answer 2

遞歸是必經之路。 參見@TJ Crowder的答案使用jQuery遍歷嵌套對象