[英]Swift / core data fetching to array when sending message to multiple recipients
我正在嘗試從核心數據中獲取電話號碼,並將短信發送給多個收件人。
用for循環獲取數字,但是我不能在for循環之外使用它。 (我可以將它們寫入控制台,但不能寫入“ messageVC.recipients = tela;”。
錯誤是“使用無法解析的標識符”,我正在使用Xcode6
這是我的代碼;
@IBAction func sendMessages(sender: AnyObject) {
let entityDescription =
NSEntityDescription.entityForName("Person",
inManagedObjectContext: managedObjectContext!)
let request = NSFetchRequest()
request.entity = entityDescription
var error: NSError?
var objects = managedObjectContext?.executeFetchRequest(request,
error: &error)
if let results = objects {
if results.count > 0 {
var saydir = results.count - 1
for (var i=0; i < results.count; i++) {
let match = results[i] as NSManagedObject
var tela = match.valueForKey("number") as String
println(tela)
}
} else {
}
}
var messageVC = MFMessageComposeViewController()
messageVC.recipients = tela;
messageVC.body = "text1" + "text2";
messageVC.messageComposeDelegate = self;
self.presentViewController(messageVC, animated: false, completion: nil)
}
var tela = match.valueForKey("number") as String
的var tela = match.valueForKey("number") as String
范圍在for循環內(即,在for循環外無法訪問)。
您要么必須:
tela
變量旁邊執行操作。 編輯1:
代碼可能是這樣的(未經測試):
@IBAction func sendMessages(sender: AnyObject) {
let entityDescription =
NSEntityDescription.entityForName("Person",
inManagedObjectContext: managedObjectContext!)
let request = NSFetchRequest()
request.entity = entityDescription
var error: NSError?
var recipients = [String]()
if let results = managedObjectContext?.executeFetchRequest(request,
error: &error) {
if results.count > 0 {
var saydir = results.count - 1
for (var i=0; i < results.count; i++) {
let match = results[i] as NSManagedObject
var tela = match.valueForKey("number") as String
println(tela)
recipients.append(tela)
}
} else {
}
}
var messageVC = MFMessageComposeViewController()
messageVC.recipients = recipients;
messageVC.body = "text1" + "text2";
messageVC.messageComposeDelegate = self;
self.presentViewController(messageVC, animated: false, completion: nil)
}
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.