JPA SET IDENTITY_INSERT無效

Question

我想從我的代碼中從JPA運行此查詢。 但它不起作用。

請幫忙。

SET IDENTITY_INSERT "+tableName+" ON

UPDATE

確切的代碼行是這樣的

Query query = entityManager.createNativeQuery("SET IDENTITY_INSERT   [tableName] ON");
int updated = query.executeUpdate();

它給出了更新的0。 不對此行執行給出任何錯誤。 但是當在此之后嘗試插入時，它會給出下面的約束違例異常。

2015-03-09 15:46:52,922 WARN  org.hibernate.util.JDBCExceptionReporter.logExceptions:233 - SQL Error: 544, SQLState: 23000
2015-03-09 15:46:52,923 ERROR org.hibernate.util.JDBCExceptionReporter.logExceptions:234 - Cannot insert explicit value for identity column in table 'table_name' when IDENTITY_INSERT is set to OFF.
2015-03-09 15:46:52,924 ERROR org.hibernate.event.def.AbstractFlushingEventListener.performExecutions:324 - Could not synchronize database state with session
org.hibernate.exception.ConstraintViolationException: could not insert: [com.entities.EntityName]

Answer 1

這和這幫助我，我有如下這方面的工作。

同樣從這個鏈接我得到的答案是JPA不支持DDL操作。

如果有人可以添加這個答案，那也會很棒。

EntityTransaction tx = entityManager.getTransaction();

try {
// entitiesMap hold the entity class/table name pairs which have autoincrement primary keys in the sql server database
if(entitiesMap.containsKey(entityName)){
    String tableName = entitiesMap.get(entityName);
    Session session = (Session) entityManager.getDelegate();
    session.connection().createStatement().execute("SET IDENTITY_INSERT [dbo]." + tableName + " ON");
}

tx.begin();
entityObject = jpaTemplate.merge(entity);
tx.commit();

if(entitiesMap.containsKey(entityName)){
    String tableName = entitiesMap.get(entityName);
    Session session = (Session) entityManager.getDelegate();
    session.connection().createStatement().execute("SET IDENTITY_INSERT [dbo]." + tableName + " OFF");
}

return entityObject;
} catch (Exception e) {
}finally{
}

Answer 2

您不希望表名周圍有引號。

=“SET IDENTITY_INSERT”+ tableName +“ON”