[英]Bash script if statement with multiple conditions
我正在嘗試為一個無所事事的人偶開發環境創建一個簡單的bash shell腳本配置程序,該程序檢查/ tmp / puppet-modules-up-to-date是否存在並在特定時間范圍內創建(准確地說是14天)。 我正在努力使用這個簡單的腳本。 任何幫助表示贊賞。
#!/bin/bash
if [[ ! -f /tmp/.puppet-modules-up-to-date ]] && [[ ! (find /tmp/.puppet-modules-up-to-date -mtime -14 | grep puppet) ]]; then
puppet_dir=/etc/puppet
echo 'Copying Puppetfile into place'
cp /vagrant/puppet/Puppetfile $puppet_dir
cd $puppet_dir
echo 'Installing puppet modules into place'
librarian-puppet install
echo 'Updating previously installed puppet modules'
librarian-puppet update
touch /tmp/.puppet-modules-up-to-date
fi
只是給我以下錯誤:
==> default: /tmp/vagrant-shell: line 3: conditional binary operator expected
==> default: /tmp/vagrant-shell: line 3: expected `)'
==> default: /tmp/vagrant-shell: line 3: syntax error near `/tmp/.puppet-modules-up-to-date'
==> default: /tmp/vagrant-shell: line 3: `if [[ ! -f /tmp/.puppet-modules-up-to-date ]] && [[ ! (find /tmp/.puppet-modules-up-to-date -mtime -14 | grep puppet) ]]; then'
問題似乎在這里:
[[ ! (find /tmp/.puppet-modules-up-to-date -mtime -14 | grep puppet) ]];
由於這實際上並沒有捕獲find/grep
輸出,您可以使用$(find...)
命令來完成。
但是,您可以使用grep -q
更好地處理這種情況:
find /tmp/.puppet-modules-up-to-date -mtime -14 | grep -vq puppet
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