[英]Case statement in Having clause in mysql
我有一個存儲過程,我必須根據操作員檢查比較一些結果。 運算符可以是' >
'或' <
'我的查詢是:
SELECT COUNT(LastWeekId) , COUNT(PreviousToLastWeekId)
FROM
(
SELECT `transaction_id` AS LastWeekId, NULL AS PreviousToLastWeekId
FROM `kwt_transaction`
WHERE `statusid` =1000
AND (createdon BETWEEN CONCAT(DATE_SUB(DATE(NOW()), INTERVAL 7 DAY)," 00:00:00") AND CONCAT(DATE_SUB(DATE(NOW()), INTERVAL 1 DAY)," 23:59:59"))
UNION
SELECT `transaction_id` AS LastWeekId, NULL AS PreviousToLastWeekId
FROM `kwt_transactions_p2p`
WHERE `statusid` =1000
AND (createdon BETWEEN CONCAT(DATE_SUB(DATE(NOW()), INTERVAL 7 DAY)," 00:00:00") AND CONCAT(DATE_SUB(DATE(NOW()), INTERVAL 1 DAY)," 23:59:59"))
UNION
SELECT NULL AS LastWeekId, `transaction_id` AS PreviousToLastWeekId
FROM `kwt_transaction`
WHERE `statusid` =1000
AND (createdon BETWEEN CONCAT(DATE_SUB(DATE(NOW()), INTERVAL 14 DAY)," 00:00:00") AND CONCAT(DATE_SUB(DATE(NOW()), INTERVAL 8 DAY)," 23:59:59"))
UNION
SELECT NULL AS LastWeekId, `transaction_id` AS PreviousToLastWeekId
FROM `kwt_transactions_p2p`
WHERE `statusid` =1000
AND (createdon BETWEEN CONCAT(DATE_SUB(DATE(NOW()), INTERVAL 14 DAY)," 00:00:00") AND CONCAT(DATE_SUB(DATE(NOW()), INTERVAL 8 DAY)," 23:59:59"))
) ttable
HAVING COUNT(LastWeekId) > COUNT(PreviousToLastWeekId)
所以我想檢查一下:
HAVING Case _operaotr
when '>'
COUNT(LastWeekId) > COUNT(PreviousToLastWeekId);
when '<'
COUNT(LastWeekId) < COUNT(PreviousToLastWeekId);
End Case;
在mysql中這可能嗎
我認為您可以這樣做:
HAVING CASE @Operator
WHEN '>' THEN COUNT(LastWeekId) > COUNT(PreviousToLastWeekId)
WHEN '<' THEN COUNT(LastWeekId) < COUNT(PreviousToLastWeekId)
WHEN '=' THEN COUNT(LastWeekId) = COUNT(PreviousToLastWeekId)
-- and so on
END
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