我無法使用Javascript使用JSON進行解析

Question

我已經閱讀了這篇文章，但我仍然不知道發生了什么。

根據大多數JSON在線數據檢查器，我的var“文本”有效，但是當我執行解析時，它什么也沒做。

這是示例代碼：

<!DOCTYPE html>
<html>
<body>

<h2>Create Object from JSON String</h2>

<p id="demo"></p>

<script>
var text = '{
"zipcodes": [
    {
        "zip": "22312",
        "city": "Alexandria",
        "state": "VA"
    },
    {
        "zip": "22030",
        "city": "Fairfax",
        "state": "VA"
    },
    {
        "zip": "22301",
        "city": "Tyson's Corner",
        "state": "VA"
    },
    {
        "zip": "20148",
        "city": "Ashburn",
        "state": "VA"
    }
]}';

obj = JSON.parse(text);
document.getElementById("demo").innerHTML =
obj.zipcodes[1].zip + " " + obj.zipcodes[1].city;
</script>

</body>
</html>

Answer 1

您有兩個問題：

JavaScript不支持多行字符串，而無需在每行上都標記一個連續符（通過\\在行末）。 我已經在示例中完成了此操作，但是將JSON包含在一行中確實更加容易。
您在字符串中使用了單引號，但字符串中包含未轉義的' 。 逃脫它，你很好。

 var text = '{ \\ "zipcodes": [\\ { \\ "zip": "22312", \\ "city": "Alexandria", \\ "state": "VA" \\ }, \\ { \\ "zip": "22030", \\ "city": "Fairfax", \\ "state": "VA" \\ }, \\ { \\ "zip": "22301", \\ "city": "Tyson\\'s Corner", \\ "state": "VA" \\ }, \\ { \\ "zip": "20148", \\ "city": "Ashburn", \\ "state": "VA" \\ } \\ ]}'; obj = JSON.parse(text); document.getElementById("demo").innerHTML = obj.zipcodes[1].zip + " " + obj.zipcodes[1].city;

 <div id='demo'></div>

Answer 2

您必須將json放在一行上並轉義'。

“泰森角”

http://jsbin.com/xumiba/1/edit?html,js，控制台，輸出

var text = '{ "zipcodes": [ { "zip": "22312", "city": "Alexandria", "state": "VA" }, { "zip": "22030", "city": "Fairfax", "state": "VA" }, { "zip": "22301", "city": "Tyson\'s Corner", "state": "VA" }, { "zip": "20148", "city":"Ashburn", "state": "VA" }]}';

Answer 3

您需要在每個字符串的新行末添加\\並轉義'字符。 這樣的事情會做：

var text = '{\
"zipcodes": [\
    {\
        "zip": "22312",\
        "city": "Alexandria",\
        "state": "VA"\
    },\
    {\
        "zip": "22030",\
        "city": "Fairfax",\
        "state": "VA"\
    },\
    {\
        "zip": "22301",\
        "city": "Tyson\'s Corner",\
        "state": "VA"\
    },\
    {\
        "zip": "20148",\
        "city": "Ashburn",\
        "state": "VA"\
    }\
]}';

obj = JSON.parse(text);

console.log(obj.zipcodes[1].zip + " " + obj.zipcodes[1].city);
document.getElementById("demo").innerHTML =
obj.zipcodes[1].zip + " " + obj.zipcodes[1].city;

這是一個jsfiddle鏈接：

http://jsfiddle.net/0retway7/

我無法使用Javascript使用JSON進行解析

問題描述

3 個解決方案

解決方案1
3 已采納 2015-03-11 15:56:13

解決方案2
2 2015-03-11 15:52:57

解決方案3
0 2015-03-11 15:58:02

我無法使用Javascript使用JSON進行解析

問題描述

3 個解決方案

解決方案1 3 已采納 2015-03-11 15:56:13

解決方案2 2 2015-03-11 15:52:57

解決方案3 0 2015-03-11 15:58:02

解決方案1
3 已采納 2015-03-11 15:56:13

解決方案2
2 2015-03-11 15:52:57

解決方案3
0 2015-03-11 15:58:02