while循環遇到麻煩

Question

我不明白為什么當我運行這個小程序時屏幕上什么都沒顯示？ while循環甚至開始了嗎？

#include <stdio.h>
#include <string.h>

int main()
{
  char word[20]; 
  char TryAgain[20] = "y";
  int WordLength = 0;

  while (strcmp(TryAgain, "y"))
  {
    printf("\t\t\t Word \n\n");
    printf("What is your word, bird?\n");
    scanf("%s", word);
    getchar();

    WordLength = strlen(word); 

    printf("Result: "); 
    for (int i = 0; i < WordLength; ++i)
    {
        printf("%c*", word[i]);
    }
    printf("\nWould you like to try another word? [y/n]\n");
    scanf("%s", TryAgain);
  }

  getchar();
  return 0;
}

Answer 1

如果strcmp的參數相同，則返回0，因此在第一次迭代時，while循環將檢查while(0) 。 0等於布爾檢查中的false ，因此將跳過while循環。 試試while(!strcmp(TryAgain, "y")) 。

Answer 2

我更喜歡將其更改為“ do-while”

do {
  printf("\nWould you like to try another word? [y/n]\n");
  scanf("%s", TryAgain);
} while (TryAgain=="y" || TryAgain=="Y");

TryAgain必須為布爾值。 再見