[英]Show PopUp at the center of anchor(view)
我想根據錨點位置顯示彈出窗口。
當前,它在錨點的左上角顯示彈出窗口,但我想在錨點的中心位置而不是向左顯示彈出窗口。
這是我的代碼:
public void show (View anchor) {
preShow();
int xPos, yPos,arrowPos;
mDidAction = false;
int[] location = new int[2];
anchor.getLocationOnScreen(location);
Rect anchorRect = new Rect(location[0], location[1], location[0] + anchor.getWidth(), location[1]
+ anchor.getHeight());
//mRootView.setLayoutParams(new LayoutParams(LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT));
mRootView.measure(LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT);
int rootHeight = mRootView.getMeasuredHeight();
if (rootWidth == 0) {
rootWidth = mRootView.getMeasuredWidth();;
}
int screenWidth = mWindowManager.getDefaultDisplay().getWidth();
int screenHeight = mWindowManager.getDefaultDisplay().getHeight();
//automatically get X coord of popup (top left)
if ((anchorRect.left + rootWidth) > screenWidth) {
xPos = anchorRect.left - (rootWidth-anchor.getWidth());
xPos = (xPos < 0) ? 0 : xPos;
arrowPos = anchorRect.centerX()-xPos;
} else {
if (anchor.getWidth() > rootWidth) {
xPos = anchorRect.centerX() - (rootWidth/2);
} else {
xPos = anchorRect.left;
}
arrowPos = anchorRect.centerX()-xPos;
}
int dyTop = anchorRect.top;
// //automatically get X coord of popup (top left)
int dyBottom = screenHeight - anchorRect.bottom;
boolean onTop = (dyTop > dyBottom) ? true : false;
if (onTop) {
if (rootHeight > dyTop) {
yPos = 15;
LayoutParams l = mScroller.getLayoutParams();
l.height = dyTop - anchor.getHeight();
} else {
yPos = anchorRect.top - rootHeight;
}
} else {
yPos = anchorRect.bottom;
if (rootHeight > dyBottom) {
LayoutParams l = mScroller.getLayoutParams();
l.height = dyBottom;
}
}
mWindow.showAtLocation(anchor, Gravity.NO_GRAVITY, xPos,yPos);
}
請建議
代替這個
mWindow.showAtLocation(anchor, Gravity.NO_GRAVITY, xPos,yPos);
試試這個可能對您有幫助...
mWindow.showAtLocation(anchor, Gravity.CENTER, 0, 0);
要么
mWindow.showAtLocation(anchor, Gravity.CENTER, anchorwidth / 2, anchorheight / 2);
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.