選擇“ Count of 1”字段的值大於一個值，而另一個字段的值小於一個值

Question

我正在嘗試返回客戶表中statustype ='dc'的所有實例，然后針對這些結果，FC上的計數> 1，Address1上的計數為1。

IE：

FC    Address1
111    abc
111    cde
432    qqq
432    qqq

我需要返回111 FC結果，因為它們的address1不同。 但是我不需要返回432 FC結果，因為該FC有多個地址

 SELECT *
  FROM Customers
  where FC IN( select FC from Customers where StatusType= 'dc'
  group by FC having COUNT(FC) > 1 and COUNT(Address1) < 2

)
  order by FC, Address1

我也試過= 1而不是<2

Answer 1

如果需要有關具有多個唯一地址的FC的詳細信息，則此查詢將為您提供：

select c.* from customers c
join (
    select FC
    from customers
    where statustype = 'dc'
    group by fc having count(distinct Address1) > 1
) a on c.FC = a.FC

Answer 2

您還需要按地址1分組。

SELECT *
FROM Customers
where FC IN( select FC from Customers where StatusType= 'dc'
group by FC, Address1 having COUNT(FC) > 1 and COUNT(Address1) < 2)
order by FC, Address1

Answer 3

嘗試使用Distinct COUNT

SELECT *
FROM   Customers
WHERE  FC IN(SELECT FC
             FROM   Customers
             WHERE  StatusType = 'dc'
             GROUP  BY FC
             HAVING Count(DISTINCT Address1) > 1)
ORDER  BY FC,
          Address1