[英]Laravel 5.3 Eloquent Join table with multiple condition join having count
[英]laravel eloquent JOIN ON multiple condition
我有一個表調用銀行,它存儲國家銀行名稱、代碼等
我有一個名為site_banks的表,其中存儲了銀行帳戶、銀行持有人姓名和引用銀行的外國銀行ID
我有一個表叫deposit_records ,它存儲存款時間、存款收據、狀態等和引用site_banks 的外國銀行 ID
對於deposit_records ,狀態字段,值 1 表示成功
現在我想計算每個site_banks的總收入
但我不希望每一行site_banks調用一個查詢來計數,這將有很多 sql 查詢調用
所以我想我可以使用join ,下面是site_banks模型文件, scopeGroupAllSiteBanksByBranch是我想收集所有 site_banks 的地方,加入 SUM,返回數組
但即使我有大約 200 個site_banks行,很多deposit_records行是status = '1' ,但scopeGroupAllSiteBanksByBranch將始終只返回一行,我不明白為什么,我復制了 sql 查詢以在 mysql 中運行,是相同的結果,只有 1 行返回。
<?php
use Illuminate\Database\Eloquent\SoftDeletingTrait;
class SiteBanks extends \LaravelBook\Ardent\Ardent {
use SoftDeletingTrait;
/**
* The database table used by the model.
*
* @var string
*/
protected $table = 'site_banks';
protected $dates = ['deleted_at'];
protected $fillable = array('bank_id', 'bank_name', 'bank_account', 'bank_holder', 'bank_username', 'bank_password', 'min_deposit', 'max_deposit', 'daily_max_deposit');
public static $rules = array(
'bank_id' => 'required|exists:banks,id',
'bank_name' => 'required|min:1',
'bank_account' => 'required|min:1|numberonly',
'bank_holder' => 'required|min:1',
'bank_username' => 'required|min:1',
'bank_password' => 'required|min:1',
'min_deposit' => 'required|fund',
'max_deposit' => 'required|fund',
'daily_max_deposit' => 'required|fund',
);
public function bank() {
return $this->belongsTo('Banks', 'bank_id');
}
public function transactions() {
return $this->hasMany('Deposit', 'bank_id', 'id');
}
public function transactionsDone() {
return $this->hasMany('Deposit', 'bank_id', 'id')->where('status', '=', 1);
}
public function transactionsBanned() {
return $this->hasMany('Deposit', 'bank_id', 'id')->where('status', '=', 2);
}
public function transactionsPending() {
return $this->hasMany('Deposit', 'bank_id', 'id')->where('status', '=', 0);
}
public function setBankPasswordAttribute($value) {
$this->attributes['bank_password'] = Crypt::encrypt($value);
}
public function getBankPasswordAttribute() {
return Crypt::decrypt($this->attributes['bank_password']);
}
public function scopeGetAvailableBanks($query) {
$query->where(DB::raw("(current_deposit < daily_max_deposit) OR (current_deposit IS NULL) OR (DATE(last_deposit) != DATE(NOW()) OR last_deposit IS NULL) OR (DATE(last_deposit) = DATE(NOW()) && current_deposit < daily_max_deposit)"));
$query->groupBy('bank_id')->orderBy('id', 'ASC');
}
public function scopeGroupAllSiteBanksByBranch($query) {
$bank = \SiteBanks::withTrashed()
->leftJoin('deposit_records', function($q) {
$q->on('deposit_records.bank_id', '=', 'site_banks.id');
$q->where('deposit_records.status', '=', 1, 'and');
})
->select(array('site_banks.*', DB::raw('SUM(`deposit_records`.`deposit_amount`) AS `total_income`')))
->get();
// $bank = \SiteBanks::withTrashed()->get();
$bank->load('bank');
$banks = array();
foreach($bank as $key => $var) {
$arr = array();
$arr = $var->toArray();
$arr['income'] = $var->total_income;
$banks[$var->bank->bank_name][] = $arr;
}
return $banks;
}
}
SQL查詢
選擇
site_banks
.*, SUM(deposit_records
.deposit_amount
) AStotal_income
fromsite_banks
left 加入deposit_records
ondeposit_records
。bank_id
=site_banks
。id
和deposit_records
。status
= '1'
var_dump來自scopeGroupAllBanksByBranch的結果
array (size=1)
'BANKNAME' =>
array (size=1)
0 =>
array (size=20)
'id' => int 1
'bank_id' => int 4
'bank_name' => string 'BANKNAME' (length=6)
'bank_account' => string '123456789' (length=9)
'bank_holder' => string 'ACCOUNT HOLDER NAME' (length=11)
'bank_username' => string 'username' (length=8)
'bank_password' => string 'hehethisispassword' (length=18)
'min_deposit' => string '400.00' (length=6)
'max_deposit' => string '9999.99' (length=7)
'daily_max_deposit' => string '25500.00' (length=8)
'last_deposit' => string '2015-02-05 03:04:00' (length=19)
'current_deposit' => string '0.00' (length=4)
'created_by' => int 1
'updated_by' => null
'created_at' => string '2015-02-04 08:21:16' (length=19)
'updated_at' => string '2015-02-04 08:21:16' (length=19)
'deleted_at' => null
'total_income' => string '1722.00' (length=7)
'bank' =>
array (size=7)
...
'income' => string '1722.00' (length=7)
您可以按照代碼解決您的問題
SQL查詢
LEFT JOIN bookings
ON rooms.id = bookings.room_type_id AND (bookings.arrival = ? OR bookings.departure = ? )
Laravel 加入多個條件
->join('bookings', function($join) use ($key1, $key2)
{
$join->on('rooms.id', '=', 'bookings.room_type_id');
$join->on(function($query) use ($key1, $key2)
{
$query->on('bookings.arrival', '=', $key1);
$query->orOn('departure', '=',$key2);
});
})
public function scopeGroupAllSiteBanksByBranch($query) {
$bank = \SiteBanks::withTrashed()
->leftJoin('deposit_records', function($q) {
$q->on('deposit_records.bank_id', '=', 'site_banks.id');
$q->where('deposit_records.status', '=', 1, 'and');
})
->select(array('site_banks.*', DB::raw('SUM(`deposit_records`.`deposit_amount`) AS `total_income`')))
->groupBy('site_banks.id')
->get();
我找到了解決方案,然后groupBy('site_banks.id')就設置好了。
這是解決方案。 您可以加入多個條件。
$query = self::select('websites.id','websites.website_url','cron_tracking_details.cron_type');
$query = $query->leftJoin('cron_tracking_details',function ($join){
$join->on(function ($queryone){
$queryone->on('websites.id','=','cron_tracking_details.website_id');
$queryone->where('cron_tracking_details.cron_type','=',"sitemap_create");
$queryone->Where('cron_tracking_details.cron_date','<','2020-11-19');
});
});
$query = $query->orderBy('cron_tracking_details.id','desc');
$query = $query->limit(1);
return $query = $query->get();
此代碼將准備這樣的查詢。
select `websites`.`id`, `websites`.`website_url`, `cron_tracking_details`.`cron_type` from `websites` left join `cron_tracking_details` on (`websites`.`id` = `cron_tracking_details`.`website_id` and `cron_tracking_details`.`cron_type` = ? and `cron_tracking_details`.`cron_date` < ?) order by `cron_tracking_details`.`id` desc limit 1
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