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[英]JSON fatal error: unexpectedly found nil while unwrapping an Optional value
[英]“fatal error: unexpectedly found nil while unwrapping an Optional value” when parsing JSON
注意:我想知道拒絕投票的原因。 我認為使用適當的格式是個很合法的問題。 我並不真的在乎選票,因為我只是在這里學習,但是誰在不加解釋的情況下給出棄權票,則會阻止很多人去問和學習。
我寫了下面的代碼,用於從Web服務獲取json,當我在新的“單視圖項目”中運行json時,效果很好,但它給出了**fatal error: unexpectedly found nil while unwrapping an Optional value**
在添加**fatal error: unexpectedly found nil while unwrapping an Optional value**
時**fatal error: unexpectedly found nil while unwrapping an Optional value**
當我添加它時我的項目。 您還可以從下面的屏幕截圖中查看出了問題所在。
碼:
import UIKit
class NewsViewController: UIViewController {
@IBOutlet var newsTableView: UITableView!
var newsTitles : NSMutableArray = NSMutableArray() // will contain news contents from API
var newsURLs : NSMutableArray = NSMutableArray() // will contain news URLs from API
var newsResponse : NSMutableArray = NSMutableArray() // will contain server response
override func viewDidLoad() {
super.viewDidLoad()
getNews()
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
// Calling News Service
func getNews(){
var serviceParam: AnyObject = NSUserDefaults.standardUserDefaults().objectForKey("key4news")!
var apiURL = "http://myIP/myWebService?search_text=\(serviceParam)"
println(apiURL)
var request : NSMutableURLRequest = NSMutableURLRequest()
request.URL = NSURL(string: apiURL)
request.HTTPMethod = "GET"
NSURLConnection.sendAsynchronousRequest(request, queue: NSOperationQueue(), completionHandler:{ (response:NSURLResponse!, data: NSData!, error: NSError!) -> Void in
var error: AutoreleasingUnsafeMutablePointer<NSError?> = nil
let jsonResult: NSDictionary! = NSJSONSerialization.JSONObjectWithData(data, options:NSJSONReadingOptions.MutableContainers, error: error) as? NSDictionary
if (jsonResult != nil) {
self.newsResponse = jsonResult.objectForKey("result") as NSMutableArray
for var i=0; i<self.newsResponse.count; i++ {
self.newsTitles[i] = self.newsResponse[i].objectForKey("title")! as NSString
self.newsURLs[i] = self.newsResponse[i].objectForKey("link")! as NSString
println("news title: \(self.newsTitles[i])")
println("news link: \(self.newsURLs[i])")
println("\n\n")
}
} else {
// couldn't load JSON, look at error
println("jsonResult is nil")
}
})
}
func tableView(tableView:UITableView!, numberOfRowsInSection section:Int) -> Int
{
return 10
}
func tableView(tableView: UITableView!, cellForRowAtIndexPath indexPath: NSIndexPath!) -> UITableViewCell!
{
let cell:UITableViewCell=UITableViewCell(style: UITableViewCellStyle.Subtitle, reuseIdentifier: "newsItem")
cell.textLabel?.text = newsTitles[indexPath.row] as NSString
return cell
}
func tableView(tableView: UITableView!, didSelectRowAtIndexPath indexPath: NSIndexPath!) {
println("you've touched tableviewcell")
}
/*
// MARK: - Navigation
// In a storyboard-based application, you will often want to do a little preparation before navigation
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
// Get the new view controller using segue.destinationViewController.
// Pass the selected object to the new view controller.
}
}
這是我的Web服務的JSON格式(它在“結果”數組中最多返回10個項目):
{
"status": "ok",
"result": [
{
"date added": "2014-12-29 00:00:00",
"link": "http:link3.com",
"description": "description of first news",
"title": "title of first news"
},
{
"date added": "2013-10-15 00:00:00",
"link": "http:link3.com",
"description": "description of second news",
"title": "title of second news"
},
{
"date added": "2013-04-09 00:00:00",
"link": "http:link3.com",
"description": "description of third news",
"title": "title of third news"
}
]
}
我怎樣才能解決這個問題?
我認為您沒有從服務器獲取數據作為響應,這就是為什么出現此錯誤的原因。
您需要進行網址編碼。
您的密碼
var serviceParam: AnyObject = NSUserDefaults.standardUserDefaults().objectForKey("key4news")!
var apiURL = "http://myIP/myWebService?search_text=\(serviceParam)"
需要像
var serviceParam: AnyObject = NSUserDefaults.standardUserDefaults().objectForKey("key4news")!
serviceParam = serviceParam.stringByAddingPercentEncodingWithAllowedCharacters(.URLHostAllowedCharacterSet())!
var apiURL = "http://myIP/myWebService?search_text=\(serviceParam)"
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