[英]python - most recent file in list
我有這樣的清單-
list = [['multinational_intel_2014-10-22T110406Z.zip', '2014 10 22 11:05:19'],
['multinational_intel_2014-10-24T140006Z.zip', '2014 10 24 14:02:51'],
['multinational_intel_2014-11-12T104622Z.zip', '2014 11 12 10:47:49'],
['multinational_intel_2014-11-10T131155Z.zip', '2014 11 10 13:13:57'],
['multinational_intel_2014-11-14T172344Z.zip', '2014 11 14 17:25:17'],
['multinational_intel_2014-11-11T103518Z.zip', '2014 11 11 10:36:47']]
我想掃描列表並獲取與最近日期關聯的文件。
對於list
我的預期輸出將是-
multinational_intel_2014-11-14T172344Z.zip
一種方法是使用sorted :
list = [['multinational_intel_2014-10-22T110406Z.zip', '2014 10 22 11:05:19'],
['multinational_intel_2014-10-24T140006Z.zip', '2014 10 24 14:02:51'],
['multinational_intel_2014-11-12T104622Z.zip', '2014 11 12 10:47:49'],
['multinational_intel_2014-11-10T131155Z.zip', '2014 11 10 13:13:57'],
['multinational_intel_2014-11-14T172344Z.zip', '2014 11 14 17:25:17'],
['multinational_intel_2014-11-11T103518Z.zip', '2014 11 11 10:36:47']]
sorted_list = sorted(list, key=lambda x: x[1], reverse=True)
most_recent = sorted_list[0][0]
print most_recent
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