PHP的PDO哎呀獲取數據不起作用

Question

類PHP

<?php

    class product extends db {

        function viewCat(){

            $dbcon = new db();
            $connn = $dbcon->dbcon();

            try {
                $stmt = $connn->prepare("SELECT * FROM `cat`");

                $resultcat = $stmt->execute();

                return $resultcat;

            } catch (PDOException $e) {
                echo 'Error: ' . $e->getMessage();
            }

        }  

    }

    ?>

風景

<?php
$menu = new product();

$resultmenux = $menu->viewCat();


    foreach ($resultcatx as $row) {
        print_r($row);
    }

?>

我得到的錯誤是

警告：為foreach（）提供了無效的參數

Answer 1

應該是這樣的：

$resultmenux = $menu->viewCat();


foreach ($resultmenux as $row) {
    print_r($row);
}

Answer 2

在您的類文件中應該是，正如我評論的那樣，您不是在獲取數據

$stmt = $connn->prepare("SELECT * FROM `cat`");

$stmt->execute();

$resultcat = $stml->fetchAll(PDO::FETCH_ASSOC); // this line was missing

return $resultcat;

並在shankhan回答的視圖文件中

$resultmenux = $menu->viewCat();    

foreach ($resultmenux as $row) {
    print_r($row);
}