[英]MySQL select where duplicates in field, not returning all records
我正在嘗試選擇記錄與另一個記錄共享一個字段值的記錄,但是我嘗試的查詢僅返回一個實例。 例如,在此表中:
COUNTRY LANGUAGE
Mexico Spanish
Portugal Portuguese
Russia Russian
Spain Spanish
Thailand Thai
United Kingdom English
United States English
...我想返回:
COUNTRY LANGUAGE
Mexico Spanish
Spain Spanish
United Kingdom English
United States English
使用方法:
SELECT * FROM `table` GROUP BY `language` HAVING COUNT(language) > 1
我只會得到:
COUNTRY LANGUAGE
Spain Spanish
United Kingdom English
我在哪里錯了?
找到了解決方案:
SELECT * FROM `TABLE` WHERE `language` IN (
SELECT * GROUP BY `language` HAVING COUNT(primary_language) > 1
)
您需要將其分為兩個步驟。 獲取子選擇中的語言列表,然后獲取行:
SELECT * FROM country_language其中的語言(選擇語言FROM country_language GROUP BY語言的語言擁有計數(*)> 1)
嘗試這個
SELECT COUNTRY,從
table
語言WHERE LANGUING IN(從table
GROUP BY中選擇語言,language
HAVING COUNT(語言)> 1);
您需要一個子查詢,該查詢返回一組具有多種國家/地區語言的語言。 然后選擇該語言集中的所有行:
SELECT *
FROM `table`
WHERE language IN
(
SELECT language FROM `table` GROUP BY `language` HAVING COUNT(*) > 1
)
我沒有那么有經驗,但這應該可以解決問題!
SELECT Country
from (SELECT Country, count(Lang) as Langs
FROM Land
Group by Lang) as table2
WHERE table2.Langs!=1
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.