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將Integer放入Java的嵌套Hashmap中

[英]Put Integer in a nested Hashmap in Java

我在此結構中有一個嵌套的Hashmap: HashMap<Integer,HashMap<Integer, Integer>> 我試圖按此順序放置數據:

{
item_id1 -> { {user_id1 -> rating} , {user_id2 -> rating} ...}
item_id2 -> ...
...
} 

問題是錯誤的user_id插入了錯誤的item_id ,因此給出了錯誤的評分。 我認為內部HashMap的對象引用存在問題,但是我不確定。

public HashMap<Integer, HashMap<Integer, Integer>> getUserRating() throws SQLException {

    HashMap<Integer,HashMap<Integer, Integer>> ratings = 
            new HashMap<Integer,HashMap<Integer, Integer>>();

    String query = "SELECT * FROM rating";
    resultSet = statement.executeQuery(query);

    Integer rating;
    Integer user;
    Integer item;
    HashMap<Integer,Integer> innerHashMap =  null;
    while(resultSet.next()) {
        item = resultSet.getInt(2);
        user = resultSet.getInt(1);
        rating = resultSet.getInt(3);

        if(innerHashMap == null) {
            innerHashMap = new HashMap<Integer,Integer>();
        }
        innerHashMap.put(user, rating);
        ratings.put(item,innerHashMap);

    }

    // item_id = 400 , user_id = 44490. Should print rating = 4, but prints 2
    System.out.println(ratings.get(400).get(44490));

    return ratings;

}

謝謝@JB Nizet。 這有效:

    public HashMap<Integer, HashMap<Integer, Integer>> getUserRating() throws SQLException {
    HashMap<Integer,HashMap<Integer, Integer>> ratings = 
            new HashMap<Integer,HashMap<Integer, Integer>>();

    String query = "SELECT * FROM rating";
    resultSet = statement.executeQuery(query);

    Integer rating;
    Integer user;
    Integer item;

    HashMap<Integer,Integer> innerHashMap =  null;
    while(resultSet.next()) {
        item = resultSet.getInt(2);
        user = resultSet.getInt(1);
        rating = resultSet.getInt(3);

        if(ratings.get(item) == null) {
            innerHashMap = new HashMap<Integer,Integer>();
        }

        innerHashMap.put(user, rating);
        ratings.put(item,innerHashMap);


    }

    // item_id = 400 , user_id = 44490. Should print rating = 4
    System.out.println(ratings.get(400).get(44490));

    return ratings;

}

您應該嘗試在每次迭代中重新創建一個新的innerHashMap。

實際上,您只有一個,因此您可以在其中混合值。

if有條件則刪除

if(innerHashMap == null) {
    innerHashMap = new HashMap<Integer,Integer>();
}

由於您需要為每個項目id創建一個新的HashMap,因此您可以每次創建新的innerHashMap

while(resultSet.next()) {
   item = resultSet.getInt(2);
   user = resultSet.getInt(1);
   rating = resultSet.getInt(3);
   innerHashMap = new HashMap<Integer,Integer>(); <--- New Instance every time
   innerHashMap.put(user, rating);
   ratings.put(item,innerHashMap);
}

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