http出站網關httpstatuscodeexception

Question

如果http出站網關拋出httpstatuscodeexception ...，它將冒泡到我調用網關方法的地方。 我似乎無法在那兒捕捉到異常

我有以下配置

<int:channel id="responseChannel" />

<int:gateway id="someGateway"  service-interface="someinterface"       default-request-channel="requestChannel"      default-reply-channel="responseChannel"        default-reply-timeout="${reply.timeout}"> 
<int:method name ="somemethod">

</int:gateway> 

<int:chain id="some-gateway-chain" input-channel="requestChannel" output-    channel="responseChannel">  
<int:object-to-json-transformer />
<int-http:outbound-gateway       url-expression="some url"         http-method="POST"         expected-response-type-expression="some.RESPONSE_TYPE"     request-factory="somehttpClientFactory" reply-timeout="${reply.timeout}"/>
</int:chain>

編輯：------------------------------------------------ -------

我可以做下面的事情嗎

<int:service-activator input-channel="errorChannel" output-channel="some other channel"> 

<int-groovy:script> how do i check if the payload.message.cause is a httpstatuscodeexception and then throw it from here 
</int-groovy:script> </int:service-activator>

Answer 1

將error-channel添加到<int:gateway/>並在那里處理異常。 錯誤通道上的消息是一個ErrorMessage ，其有效負載為MessagingException ，其屬性為failedMessage和cause 。

錯誤流可以引發另一個異常或返回其他結果。

回應您的編輯 ：

呃...

if (payload.cause instanceof ...) {
    throw payload.cause
}
someOtherResult