為什么我的PHP不返回MySQL存儲過程？

Question

好吧，我有我編寫的這個MySQL存儲過程，如果我在phpMyAdmin中運行以下命令，一切都會正確返回：

SELECT game_name,urlfriendly(game_name) AS game_name2 FROM games

但是，如果我嘗試運行以下代碼，則會出現錯誤“警告：/filepath.php中為第＃行的foreach（）提供了無效的參數”

foreach ($this->database->query("SELECT game_name,urlfriendly(game_name) AS game_name2 FROM games") as $games)
{
    echo $games["game_name"] . " " . $games["game_name2"];
}

但是，如果運行此命令，一切正常：

foreach ($this->database->query("SELECT game_name FROM games") as $games)
{
    echo $games["game_name"];
}

意味着存儲的過程不會返回到PHP。

有任何想法嗎？

編輯這是存儲的過程（但我懷疑這是問題，因為phpMyAdmin正在從中拉回值）

分隔符//

DROP FUNCTION urlfriendly
//
CREATE FUNCTION urlfriendly (unsafe TEXT) RETURNS TEXT

DETERMINISTIC

BEGIN

DECLARE safe TEXT;

SET safe = REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(LOWER(unsafe),' ','-'),'&','and'),'`',''),'~',''),'!',''),'@',''),'#',''),'$',''),'%',''),'^',''),'*',''),'(',''),')',''),'_',''),'+',''),'=',''),'[',''),'{',''),']',''),'}',''),'|',''),'\\',''),"'",""),'"',''),':',''),';',''),'<',''),',',''),'>',''),'.',''),'/',''),'?','');

RETURN safe;

END
//

EDIT2這是從MySQL返回的錯誤

execute command denied to user 'username'@'localhost' for routine 'databasename.urlfriendly' )

Answer 1

你能得到errorInfo嗎？

你能跑嗎：

GRANT EXECUTE ON `database`.* TO 'username'@'localhost'

從phpMyAdmin？