[英]store function creation error in mysql #1064
我試圖創建一個函數,即如果用戶名存在,它將以單個字符串的形式返回隨機數和字符,但是我嘗試了下面的代碼,並拋出如下所示的語法錯誤,您能幫忙找到問題嗎,我知道聲明時有問題字符串和返回的字符串,但找不到問題。 感謝提前的答復
DELIMITER //
create function verifyEmail(userName varchar(25))
RETURNS TEXT
BEGIN
if EXISTS(select * from userdetails where name = userName)
then
SELECT @randomPass := select concat( char(round(rand()*36)+1), char(round(rand()*36)+1), char(round(rand()*36)+1));
return @randomPass;
else
return "not_exist";
end if;
end //
DELIMITER //
#1064-您的SQL語法有誤; 檢查與您的MySQL服務器版本相對應的手冊以獲取正確的語法以在'select concat(char(round(rand()* 36)+1),char(round(rand()* 36)+1),char (第6行的回合(ra'
您在此行上缺少)
:
SELECT @randomPass := select concat( char(round(rand()*36)+1), char(round(rand()*36)+1), char(round(rand()*36)+1);
應該
SELECT @randomPass := select concat( char(round(rand()*36)+1), char(round(rand()*36)+1), char(round(rand()*36)+1));
Hooray,終於找到了答案。.下面的代碼將幫助解決問題的解決方案
DELIMITER //
create function verifyEmail(userName varchar(25))
RETURNS TEXT
BEGIN
DECLARE randomPass VARCHAR(8);
if EXISTS(select id from userdetails where name = userName)
THEN
SET randomPass = concat( char(rand()*25+65),char(rand()*25+65),char(rand()*25+65),char(rand()*25+65),char(rand()*25+65),char(rand()*25+65),char(rand()*25+65),char(rand()*25+65));
return randomPass;
else
return "not_exist";
end if;
end //
DELIMITER //
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