[英]Sending mail from service using smtp
我的應用程序運行一個發送和發送電子郵件的服務,該服務對於用戶而言必須是透明的,因此我使用javax.mail。
這些是我實現的類:
JSSEProvider.java
public final class JSSEProvider extends Provider {
private static final long serialVersionUID = 1L;
public JSSEProvider() {
super("HarmonyJSSE", 1.0, "Harmony JSSE Provider");
AccessController.doPrivileged(new java.security.PrivilegedAction<Void>() {
@Override
public Void run() {
put("SSLContext.TLS",
"org.apache.harmony.xnet.provider.jsse.SSLContextImpl");
put("Alg.Alias.SSLContext.TLSv1", "TLS");
put("KeyManagerFactory.X509",
"org.apache.harmony.xnet.provider.jsse.KeyManagerFactoryImpl");
put("TrustManagerFactory.X509",
"org.apache.harmony.xnet.provider.jsse.TrustManagerFactoryImpl");
return null;
}
});
}
}
MailSender.java
public class MailSender extends javax.mail.Authenticator {
private final String mailhost = "smtp.gmail.com";
private final String user;
private final String password;
private final Session session;
static {
Security.addProvider(new JSSEProvider());
}
public MailSender(String user, String password) {
this.user = user;
this.password = password;
Properties props = new Properties();
props.setProperty("mail.transport.protocol", "smtp");
props.setProperty("mail.host", mailhost);
props.put("mail.smtp.auth", "true");
props.put("mail.smtp.port", "465");
props.put("mail.smtp.socketFactory.port", "465");
props.put("mail.smtp.socketFactor.class", "javax.net.ssl.SSLSocketFactory");
props.put("mail.smtp.socketFactory.fallback", "false");
props.setProperty("mail.smtp.quitwait", "false");
session = Session.getDefaultInstance(props, this);
}
@Override
protected PasswordAuthentication getPasswordAuthentication() {
return new PasswordAuthentication(user, password);
}
public synchronized void sendMail(String subject, String body, String sender, String recipients) throws Exception {
MimeMessage message = new MimeMessage(session);
DataHandler handler = new DataHandler(new ByteArrayDataSource(body.getBytes(), "text/plain"));
message.setSender(new InternetAddress(sender));
message.setSubject(subject);
message.setDataHandler(handler);
if (recipients.indexOf(',') > 0)
message.setRecipients(Message.RecipientType.TO, InternetAddress.parse(recipients));
else
message.setRecipient(Message.RecipientType.TO, new InternetAddress(recipients));
Transport.send(message);
}
public class ByteArrayDataSource implements DataSource {
private final byte[] data;
private String type;
public ByteArrayDataSource(byte[] data, String type) {
super();
this.data = data;
this.type = type;
}
public ByteArrayDataSource(byte[] data) {
super();
this.data = data;
}
public void setType(String type) {
this.type = type;
}
@Override
public String getContentType() {
if (type == null)
return "application/octet-stream";
else
return type;
}
@Override
public InputStream getInputStream() throws IOException {
return new ByteArrayInputStream(data);
}
@Override
public String getName() {
return "ByteArrayDataSource";
}
@Override
public OutputStream getOutputStream() throws IOException {
throw new IOException("Not Supported");
}
}
}
最后,這是我從服務發送電子郵件的方式:
private void sendEmail(String email) {
String from = "mymail@gmail.com";
String pass = "mypass";
String to = email;
String subject = getString(R.string.email_subject);
String body = text_i_want_to_send;
MailSender mail = new MailSender(from, pass);
try {
mail.sendMail(subject, body, from, to);
Log.d("EMAIL", "Email sent!");
} catch (Exception e) {
Log.d("EMAIL", "Error: " + e.getMessage());
}
}
現在的問題是,當它應該發送電子郵件時,我可以在LogCat中看到引用到catch語句的異常,但是它沒有提供任何詳細信息,它只是說:
EMAIL Error: null
不得不說,我從網絡上有關使用javax.mail通過smtp發送郵件的各種教程中獲得了JSSEProvider和MailSender的案例。
所以,我不知道自己在做什么錯
編輯-
我已經找到了例外,它與在主線程上進行網絡操作有關。 因此,我現在正在使用AsyncTask並解決了這一部分。
但是現在,我有另一個例外,這次與身份驗證有關。 我已在我的電子郵件帳戶中收到一封電子郵件,告知某些人試圖訪問我的帳戶(me),而gmail已將其阻止。 那么,如何解決此身份驗證問題?
您可以為NullPointerException添加捕獲嗎? (並添加throw e)。 我猜你在某個地方有一個空指針,這樣你可以擁有更多的數據。 因此,捕獲“異常”是一個壞習慣,因為一切都會被捕獲。
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