[英]How do I retrieve an Id from a JSONObject
我在從JSONObject檢索ID並將其傳遞給String來記錄該玩家特殊難題的ID時遇到麻煩,但是在行String idString = obj.getString(“ Id”);
“我得到org.json.JSONException:Id沒有值”
我通過調用此類中的服務器來獲取此信息,該服務器檢查播放器的用戶名和密碼。
import android.os.AsyncTask;
import android.text.format.Time;
import android.util.Log;
public class GetTodaysPuzzle implements OnRetrieveHttpData {
public String GetTodaysPuzzle(String mUserName, String mPassword)
{
RetrieveHTTPData GetTodayspuzzle = new RetrieveHTTPData(this);
return GetTodayspuzzle.GetResponseData("urlString" + mUserName + "&password=" + mPassword);
}
@Override
public void onRetrieveTaskCompleted(String httpData) {
Log.i("Server Response", httpData);
}
class GetTodaysPuzzleTask extends AsyncTask<String, String, Boolean> {
@Override
protected Boolean doInBackground(String... params) {
// Get response from server
String json = GetTodaysPuzzle(params[0], params[1]);
// Check if a puzzle was returned
if (json.contains("The request is invalid"))
{
return false;
}
try
{
// Calculate today's date in order to set wordsearch date
Time today = new Time();
today.setToNow();
String formattedDate = Dates.ConvertUStoUK(today.year + "-"
+ (today.month + 1) + "-" + today.monthDay);
// Create wordsearch
WordSearch wordSearch = WordSearch.CreateWordSearch(json,
formattedDate);
if (wordSearch == null)
{
return false;
}
// Save wordsearch to collection
WordSearchDatabase.Add(wordSearch);
// WordSearchDatabase.Save();
return true;
}
catch (Exception e)
{
Log.e("GetTodaysPuzzleTask", e.getMessage());
return false;
}
}
}
}
然后將所有信息存儲到Wordsearch類的JSONArrays中。
import java.util.ArrayList;
import java.util.List;
import org.json.JSONArray;
import org.json.JSONObject;
public class WordSearch {
public String Id;
public String Date;
public List<Word> Words;
public Letter[] Letters;
public final int NUM_OF_ROWS;
public final int NUM_OF_COLS;
public int Score = -1;
private boolean containsSolution = false;
public boolean canBeSubmitted = true;
private boolean complete = false;
private boolean submitted = false;
public static WordSearch CreateWordSearch(String json, String date)
{
List<Word> listOfWords = new ArrayList<Word>();
List<String> listOfRows = new ArrayList<String>();
try
{
// Create a JSON Object from JSON string
JSONObject obj = new JSONObject(json);
// Get Id
String idString = obj.getString("Id");
// GetWords & Puzzle as JSON Arrays
JSONArray wordsArray = obj.getJSONArray("Words");
JSONArray puzzleArray = obj.getJSONArray("Grid");
// Parse Words array
for (int i = 0; i < wordsArray.length(); i++)
{
String name = wordsArray.getString(i);
Word word = new Word(name);
listOfWords.add(word);
}
// Parse Puzzle
for (int k = 0; k < puzzleArray.length(); k++)
{
String puzzle = puzzleArray.getString(k);
listOfRows.add(puzzle);
}
// Create WordSearch
return new WordSearch(idString, date, listOfWords, listOfRows,
false);
}
catch (Exception e)
{
e.printStackTrace();
return null;
}
}
}
這是我第一次在Android中使用API服務器和JSONObject,因此非常感謝您的幫助。 謝謝。
您收到此錯誤的原因是,您的響應JSON沒有“ Id”作為鍵,您只能看到“ Puzzle”:
{
"Puzzle": {
"Id": "8fb25209-863a-410b-a440-b5b57a903ee1",
"Words": ["CHATEAUX", ...],
"Grid": ["TLIOFSHTRC", ...]
}
}
您需要首先獲取“ Puzzle”對象,然后才能從該對象獲取“ Id”。
JSONObject obj = new JSONObject(json);
JSONObject puzzle = obj.getJSONObject("Puzzle");
String idString = puzzle.getString("Id");
....
id位於拼圖元素中,因此應該
JSONObject obj = new JSONObject(json);
//get puzzle object
JSONObject puzzle = obj.getJSONObject("Puzzle");
// Get Id
String idString = puzzle.getString("Id");
// GetWords & Puzzle as JSON Arrays
JSONArray wordsArray = puzzle.getJSONArray("Words");
JSONArray puzzleArray = puzzle.getJSONArray("Grid");
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