[英]rerun program before main terminates
我有這個代碼
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.println("Enter menu number: ");
int value = scanner.nextInt();
if (value == 1){
System.out.println("first");
} else if (value == 2) {
System.out.println("second");
} else if (value == 3) {
System.out.println("third");
} else {
System.out.println("closing program");
}
}
我希望行為是當輸入“ 1”作為菜單值並打印“ first”時,程序不會終止,而是返回System.out.println("Enter menu number: ");
因此可以輸入另一個菜單號,依此類推。 不知道該怎么做。
你可以做這樣的事情
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String userInput = "";
while (true) {
System.out.println("Enter menu number: ");
userInput = scanner.next();
if (userInput.trim().toUpperCase().equals("EXIT")) {
break;
}
int value = Integer.parseInt(userInput);
if(value == 1){
System.out.println("first");
}
else if(value==2){
System.out.println("second");
}
else if(value==3){
System.out.println("third");
}
}
}
在您的代碼上循環:
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int value = -1;
do { // Here you will loop until you enter something to "terminate"
System.out.println("Enter menu number: ");
value = scanner.nextInt();
if (value == 1){
System.out.println("first");
} else if (value==2){
System.out.println("second");
} else if(value==3){
System.out.println("third");
} else{
System.out.println("closing program");
}
} while (value != -1); // End condition
}
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