如何在同一個類中的變量中使用公共函數返回字符串？ PHP類

Question

我試圖在類名“設置”中使用函數“ get_setting”中返回的字符串。 我想將返回的字符串用於變量“ top_banner”。 當我嘗試使用'$ this'變量訪問該函數時，它不起作用。

class settings{

 function get_setting($name, $return="value"){
    $query = mysql_query("SELECT * FROM website_settings WHERE name='".$name."'");
    $row = mysql_fetch_array($query);
    if($row['active'] == false){//This is turned off
        return "disabled";
    }else{//this setting is active
        return $row['value'];
    }

}
    //Values
public $top_banner = $this->get_setting("top_banner");
}

Answer 1

嘗試這個：

class settings{

 function get_settings($name, $return="value"){
    $query = mysql_query("SELECT * FROM website_settings WHERE name='".$name."'");
    $row = mysql_fetch_array($query);
    if($row['active'] == false){//This is turned off
        return "disabled";
    }else{//this setting is active
        return $row['value'];
    }

   }
}
  //Values
$my_settings = new settings();
$top_banner = $my_settings->get_settings("top_banner");