如何在PHP中加入兩個MySQL查詢

Question

如何通過結合以下兩個查詢來進行單個查詢：

查詢1：

$sql = "SELECT total_ce FROM mfb_agent_status_summary AS agent LEFT JOIN mfb_servicelog AS service ON agent.sl_id = service.sl_id WHERE service.h_id LIKE ('".$value[$i]."')  AND service_add_date >= DATE_FORMAT('" . $from . "', '%Y-%m-%d') AND service_add_date <=  DATE_FORMAT('" . $to . "', '%Y-%m-%d')";

查詢2：

$query="SELECT DATE_FORMAT(service_add_date, '%d/%b/%y'), DATE_FORMAT(scan_date, '%d/%b/%y'), DATE_FORMAT(ftp_date, '%d/%b/%y'),no_of_cases_reported,no_of_cases_received,case_count_diff, DATEDIFF(ftp_date, service_add_date) FROM mfb_servicelog WHERE h_id LIKE ('".$value[$i]."') AND service_add_date >= DATE_FORMAT('" . $from . "', '%Y-%m-%d') AND service_add_date <=  DATE_FORMAT('" . $to . "', '%Y-%m-%d')";

謝謝！

Answer 1

我在這里對您的架構進行一些假設，但嘗試執行以下操作：

SELECT agent.total_ce,
       DATE_FORMAT(service.service_add_date, '%d/%b/%y'),
       DATE_FORMAT(service.scan_date, '%d/%b/%y'),
       DATE_FORMAT(service.ftp_date, '%d/%b/%y'),
       service.no_of_cases_reported,
       service.no_of_cases_received,
       service.case_count_diff,
       DATEDIFF(service.ftp_date, service.service_add_date)

FROM mfb_agent_status_summary AS agent
     LEFT JOIN mfb_servicelog AS service ON agent.sl_id = service.sl_id

WHERE service.h_id LIKE ('".$value[$i]."') AND
      agent.service_add_date >= DATE_FORMAT('" . $from . "', '%Y-%m-%d') AND
      agent.service_add_date <=  DATE_FORMAT('" . $to . "', '%Y-%m-%d')

---

我還要提及的是，您應該真正在研究准備好的語句，而不是將$from和$to直接注入查詢中。 您正在向潛在的SQL注入攻擊敞開大門。

我強烈建議通過mysqli_*函數使用PHP的PDO庫 。

Answer 2

所以我的猜測是：

$sql = "SELECT 
      agent.total_ce,
      service.*
   FROM mfb_agent_status_summary AS agent 
   LEFT JOIN (
      SELECT 
        DATE_FORMAT(service_add_date, '%d/%b/%y'), 
        DATE_FORMAT(scan_date, '%d/%b/%y'), 
        DATE_FORMAT(ftp_date, '%d/%b/%y'),
        no_of_cases_reported,
        no_of_cases_received,
        case_count_diff, 
        DATEDIFF(ftp_date, service_add_date) 
      FROM mfb_servicelog 
      WHERE h_id LIKE ('".$value[$i]."') 
        AND service_add_date >= DATE_FORMAT('" . $from . "', '%Y-%m-%d') 
        AND service_add_date <=  DATE_FORMAT('" . $to . "', '%Y-%m-%d')
   ) AS service 
   ON agent.sl_id = service.sl_id";

而且我認為您可以將“ LEFT JOIN ”替換為“ INNER JOIN”；