[英]Prolog: Find out if sum of all list elements equals N
我想檢查列表中的所有值是否合計為某個值。 到目前為止,我寫了以下內容:
list_sum([Head|Tail], Sum) :-
list_sum(Tail, Sum1),
Sum is Head + Sum1.
但是,當我嘗試list_sum([1,2,3,4], 10)
Prolog返回false
。 有人可以幫幫我嗎? 我不知道我做錯了什么。
使用clpfd !
:- use_module(library(clpfd)).
要計算整數列表的總和,只需使用clpfd庫謂詞sum/3
:
?- sum([1,2,3,4], #=, S). % Q: What is 1+2+3+4? S = 10. % A: Sum is 10 ?- sum([1,2,3,4], #=, 10). % Q: Does 1+2+3+4 equal 10? true. % A: yes, it does ?- sum([1,2,3,4], #=, 11). % Q: Does 1+2+3+4 equal 11? false. % A: no, it doesn't
一個用例,顯示使用clpfd而不是(is)/2
的好處,由@CapelliC建議:
?- [A,B,C] ins 1..sup, sum([A,B,C,A], #=, 12), labeling([], [A,B,C]). A = B, B = 1, C = 9 ; A = 1, B = 2, C = 8 ; A = 1, B = 3, C = 7 ; A = 1, B = 4, C = 6 ; A = 1, B = C, C = 5 ; A = 1, B = 6, C = 4 ; A = 1, B = 7, C = 3 ; A = 1, B = 8, C = 2 ; A = C, B = 9, C = 1 ; A = 2, B = 1, C = 7 ; A = B, B = 2, C = 6 ; A = 2, B = 3, C = 5 ; A = 2, B = C, C = 4 ; A = 2, B = 5, C = 3 ; A = C, B = 6, C = 2 ; A = 2, B = 7, C = 1 ; A = 3, B = 1, C = 5 ; A = 3, B = 2, C = 4 ; A = B, B = C, C = 3 ; A = 3, B = 4, C = 2 ; A = 3, B = 5, C = 1 ; A = 4, B = 1, C = 3 ; A = 4, B = C, C = 2 ; A = 4, B = 3, C = 1 ; A = 5, B = C, C = 1.
在我看來,這很簡單。
試試這個:
list_sum([], 0).
list_sum([Head|Tail], Sum):-
list_sum(Tail, Sum1),
Sum is Head + Sum1.
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.