[英]Get Data from selected dates by a datepicker calendar
您好我有一個datepicker日歷,我想要的是我們選擇兩個日期然后我想點擊一個按鈕它會顯示這些日期之間的所有數據。
這是我的代碼......
<?php
include_once 'header.php';
$con = mysqli_connect('localhost','root','smogi','project');
if (!$con) {
die('Could not connect: ' . mysqli_error($con));
}
$view = ($_GET['view']);
$username2 =$_SESSION['username'];
$sql="SELECT typeValue,unit,sensorValue,time FROM sensors WHERE username='$view' AND time BETWEEN $firstdate AND $lastdate ORDER BY time DESC";
$result = mysqli_query($con,$sql);
echo "<table>
<tr>
</tr>";
while($row = mysqli_fetch_array($result)) {
echo "<tr> <b>Type: </b>";
echo stripslashes($row['typeValue']) . "<br/><b>Unit: </b>";
echo stripslashes($row['unit']) . "<br/><b>Value: </b>";
echo stripslashes($row['sensorValue']) . "<br/><b>Date & Time: </b>";
echo stripslashes($row['time']) . "<br/>";
echo "--------------------------------------------------------------------------------------------------------------";
echo "<br/></tr>";
}
echo "</table>";
?>
<!doctype html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>jQuery UI Datepicker - Default functionality</title>
<link rel="stylesheet" href="//code.jquery.com/ui/1.11.4/themes/smoothness/jquery-ui.css">
<script src="//code.jquery.com/jquery-1.10.2.js"></script>
<script src="//code.jquery.com/ui/1.11.4/jquery-ui.js"></script>
<link rel="stylesheet" href="/resources/demos/style.css">
<script>
$(function() {
var firstdate = $('#firstdatepicker').datepicker({ dateFormat: 'yy-mm-dd' }).val();
//$( "#firstdatepicker" ).datepicker();
});
</script>
<script>
$(function() {
var lastdate = $('#lastdatepicker').datepicker({ dateFormat: 'yy-mm-dd' }).val();
//$( "#lastdatepicker" ).datepicker();
});
</script>
</head>
<body>
<form method="post" action="graph.php">
<p>First Date: <input type="text" id="firstdatepicker"></p>
<p>Last Date: <input type="text" id="lastdatepicker"></p>
<input type="submit" value="Get Data" name="data"/>
</form>
</body>
</html>
但它不能按我的意願工作。 你可以幫助我讓它工作嗎?
感謝您的時間 。
PS:在下圖中我們可以看到我的數據庫表是什么樣的
首先,你永遠不會定義$firstdate
$lastdate
。 你應該這樣:
$firstdate = $_POST['firstdatepicker'];
$lastdate = $_POST['lastdatepicker'];
如果它在您的“時間”列中有,則需要引用它們。
BETWEEN '$firstdate' AND '$lastdate'
使用錯誤檢查您的查詢會拋出語法錯誤
即: $result = mysqli_query($con,$sql) or die(mysqli_error($con));
MySQL將datetime
讀為YYYY-mm-dd
你正在使用dateFormat: 'yy-mm-dd'
另外,給出輸入名稱屬性:
<input type="text" id = "firstdatepicker" name = "firstdatepicker">
<input type="text" id = "lastdatepicker" name = "lastdatepicker">
並添加
$firstdate = $_POST['firstdatepicker'];
$lastdate = $_POST['lastdatepicker'];
如上所述。
你忘了在你的表單中添加name="firstdatepicker"
和name="lastdatepicker"
,你需要從$ _POST超全局數組填充你的變量(我絕望地希望你不要使用register_globals = on)。
更新的HTML部分:
<script type="text/javascript">
$(function() {
$('#firstdatepicker, #lastdatepicker').datepicker({ dateFormat: 'yy-mm-dd' });
});
</script>
<form method="post" action="graph.php">
<p>First Date: <input type="text" name="firstdatepicker" id="firstdatepicker"></p>
<p>Last Date: <input type="text" name="lastdatepicker" id="lastdatepicker"></p>
<input type="submit" value="Get Data" name="data"/>
</form>
在PHP方面:
if (isset($_POST['firstdatepicker'])) {
$firstDate= $_POST['firstdatepicker'];
$lastDate= $_POST['lastdatepicker'];
// forgot the single quotes around the dates ...
$sql="SELECT typeValue,unit,sensorValue,time FROM sensors WHERE username='$username2' AND time BETWEEN '$firstdate' AND '$lastdate' ORDER BY time DESC";
}
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