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[英]How can I specify certain field to be serialized into JSON using Jackson?
[英]How can I unwrap a specific field in a JSON using Jackson?
我有一個 JSON 有效負載,如下所示:
{
"id": 32,
"name": "[Sample] Tomorrow is today, Red printed scarf",
"primary_image": {
"id": 247,
"zoom_url": "www.site.com/in_123__14581.1393831046.1280.1280.jpg",
"thumbnail_url": "www.site.com/in_123__14581.1393831046.220.290.jpg",
"standard_url": "www.site.com/in_123__14581.1393831046.386.513.jpg",
"tiny_url": "www.site.com/in_123__14581.1393831046.44.58.jpg"
}
}
我可以打開特定字段並丟棄所有其他字段嗎? 換句話說,我可以將它直接綁定到這樣的 POJO 嗎:
public class Product {
private Integer id;
private String name;
private String standardUrl;
}
有很多方法。 您是否需要反序列化、序列化或兩者兼而有之?
反序列化的一種方法是使用將圖像作為樹節點的創建者方法:
public static class Product {
private Integer id;
private String name;
private String standardUrl;
public Product(@JsonProperty("id") Integer id,
@JsonProperty("name") String name,
@JsonProperty("primary_image") JsonNode primaryImage) {
this.id = id;
this.name = name;
this.standardUrl = primaryImage.path("standard_url").asText();
}
}
創建者不必是構造函數,您可以有一個僅用於 Jackson 反序列化的靜態方法。
不過,您必須定義一個自定義序列化程序來重新序列化它(例如,一個 StdDelegatingSerializer 和一個轉換器將字符串包裝為 ObjectNode)
有多種方法可以給這只貓剝皮,我希望你可以使用 Jackson 2,因為它提供了反序列化 Json 數據的好方法,我最喜歡的反序列化功能之一是我將在這里展示的功能(使用Builder Pattern ),因為允許您在構造實例時驗證實例(或使它們不可變!)。 對你來說,這看起來像這樣:
import com.fasterxml.jackson.annotation.JsonIgnoreProperties;
import com.fasterxml.jackson.annotation.JsonProperty;
import com.fasterxml.jackson.databind.annotation.JsonDeserialize;
import java.util.Map;
@JsonDeserialize(builder = Product.Builder.class)
public class Product {
private Integer id;
private String name;
private String standardUrl;
private Product(Builder builder) {
//Here you can make validations for your new instance.
this.id = builder.id;
this.name = builder.name;
//Here you have access to the primaryImage map in case you want to add new properties later.
this.standardUrl = builder.primaryImage.get("standard_url");
}
@Override
public String toString() {
return String.format("id [%d], name [%s], standardUrl [%s].", id, name, standardUrl);
}
@JsonIgnoreProperties(ignoreUnknown = true)
public static class Builder {
private Integer id;
private String name;
private Map<String, String> primaryImage;
public Builder withId(Integer id) {
this.id = id;
return this;
}
public Builder withName(String name) {
this.name = name;
return this;
}
@JsonProperty("primary_image")
public Builder withPrimaryImage(Map<String, String> primaryImage) {
this.primaryImage = primaryImage;
return this;
}
public Product build() {
return new Product(this);
}
}
}
為了測試它,我創建了這個類:
import com.fasterxml.jackson.databind.ObjectMapper;
import java.io.IOException;
public class Test {
public static void main(String[] args) {
String serialized = "{" +
" \"id\": 32," +
" \"name\": \"[Sample] Tomorrow is today, Red printed scarf\"," +
" \"primary_image\": {" +
" \"id\": 247," +
" \"zoom_url\": \"www.site.com/in_123__14581.1393831046.1280.1280.jpg\"," +
" \"thumbnail_url\": \"www.site.com/in_123__14581.1393831046.220.290.jpg\"," +
" \"standard_url\": \"www.site.com/in_123__14581.1393831046.386.513.jpg\"," +
" \"tiny_url\": \"www.site.com/in_123__14581.1393831046.44.58.jpg\"" +
" }" +
" }";
ObjectMapper objectMapper = new ObjectMapper();
try {
Product deserialized = objectMapper.readValue(serialized, Product.class);
System.out.print(deserialized.toString());
} catch (IOException e) {
e.printStackTrace();
}
}
輸出是(使用Product
的覆蓋toString()
方法:
id [32], name [[Sample] Tomorrow is today, Red printed scarf], standardUrl [www.site.com/in_123__14581.1393831046.386.513.jpg].
有兩種方法可以獲得您需要的響應。 對於這兩種方法,我們將使用 JsonView。
創建兩種類型的 JsonView:
public interface JViews {
public static class Public { }
public static class Product extends Public { }
}
第一種方法
@JsonView(JViews.Public.class)
public class Product {
private Integer id;
private String name;
@JsonIgnore
private Image primaryImage;
@JsonView(JViews.Product.class)
public String getStandardUrl{
return this.primaryImage.getStandardUrl();
}
}
第二種方式
一起使用 Jackson 的 @JsonView 和 @JsonUnwrapped。
@JsonView(JViews.Public.class)
public class Product {
private Integer id;
private String name;
@JsonUnwrapped
private Image primaryImage;
}
public class Image {
private String zoomUrl;
@JsonView(JViews.Product.class)
private String standardUrl;
}
@JsonUnwrapped 注釋將您的嵌套對象展平為 Product 對象。 並且 JsonView 用於過濾可訪問的字段。 在這種情況下,Product 視圖只能訪問 standardUrl 字段,結果應該是:
{
"id": 32,
"name": "[Sample] Tomorrow is today, Red printed scarf",
"standard_url": "url"
}
如果在不使用視圖的情況下展平嵌套對象,結果將如下所示:
{
"id": 32,
"name": "[Sample] Tomorrow is today, Red printed scarf",
"id":1,
"standard_url": "url",
"zoom_url":"",
...
}
Jackson 提供了 @JsonUnwrapped 注釋。
見以下鏈接:
http://jackson.codehaus.org/1.9.9/javadoc/org/codehaus/jackson/annotate/JsonUnwrapped.html
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