[英]PHP Counting with AJAX Request
我正在嘗試計算SESSION變量,但我不希望用戶看到任何刷新。
我下面的代碼的問題是,它只更改一個,然后需要刷新。 我該如何做而無需任何刷新?
test page:
<?php session_start(); ?>
<script src="../../../common/js/jquery-1.11.2.min.js"></script>
<script src="../../../common/js/jquery.touchwipe.min.js"></script>
<?php
if(empty($_SESSION['counter'])){
$_SESSION['counter'] = 1;
}
$count = $_SESSION['counter'];
?>
<div id="main"><?= $count; ?></div>
<button id="detailed">Link</button>
<script type="text/javascript">
$(document).ready(function(){
$(document).on('click','#detailed',function(){
var count = "<?= $count ?>";
count++;
$.ajax({
type: "POST",
url: "test.php",
data: {countertje: count},
success:function(data){
$('#main').html(data);
console.log(data);
}
});
})
});
</script>
do_ajax.php
<?php
session_start();
$_SESSION['counter'] = $_POST['countertje'];
echo $_SESSION['counter'];
?>
您可以在javascript中使用的東西
var count = $('#main').val();
而不是跟隨:
var count = "<?= $count ?>";
在javascript中編寫PHP代碼不是一個好主意!
<script type="text/javascript">
var count = "<?= $count ?>";
$(document).ready(function(){
$(document).on('click','#detailed',function(){
count++;
$.ajax({
type: "POST",
url: "test.php",
data: {countertje: count},
success:function(data){
$('#main').html(data);
console.log(data);
}
});
})
});
</script>
count
應該是一個全局變量
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