[英]Get localhost project name from url
如果我有一個像http://localhost/project1/
這樣的http://localhost/project1/
我如何從網址中獲取project1名稱
我正在嘗試實現的是localhost $_SERVER['HTTP_HOST'] . '/' . $project
$_SERVER['HTTP_HOST'] . '/' . $project
if (isset($_SERVER['HTTPS']) && (($_SERVER['HTTPS'] == 'on') || ($_SERVER['HTTPS'] == '1'))) {
echo 'https://' . $_SERVER['HTTP_HOST'];
} elseif ($_SERVER['HTTP_HOST'] == 'localhost') {
echo 'http://' . $_SERVER['HTTP_HOST'] . '/'; // GET PROJECT NAME Place after .'/'.
} else {
echo 'http://' . $_SERVER['HTTP_HOST'] . '/';
}
您可以使用parse_url()
函數檢索URL的部分:
$url = 'http://localhost/project1/';
$parts = parse_url($url);
print_r($parts);
輸出:
Array
(
[scheme] => http
[host] => localhost
[path] => /project1/
)
或者,如果您想直接獲取路徑:
$path = parse_url($url, PHP_URL_PATH);
// => /project1/
您可以使用$_SERVER['REQUEST_URI']
訪問請求的URI。
因此,要在您的URL中獲取項目名稱,您可以執行以下操作:
$project = explode('/', $_SERVER['REQUEST_URI'])[1];
要獲得完整的主機或項目,您可以執行以下操作:
function getFullHost()
{
$protocole = $_SERVER['REQUEST_SCHEME'].'://';
$host = $_SERVER['HTTP_HOST'] . '/';
$project = explode('/', $_SERVER['REQUEST_URI'])[1];
return $protocole . $host . $project;
}
如果您有多個子目錄,更好的方法是:
function getFullHost()
{
$protocole = $_SERVER['REQUEST_SCHEME'].'://';
$host = $_SERVER['HTTP_HOST'] . '/';
$project = explode('/', $_SERVER['REQUEST_URI']);
array_pop($project);
array_shift($project);
$path = implode('/', $project);
return $protocole . $host . $path;
}
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