如何在php中獲取周日開始日期和周日結束日期

Question

如何在php中獲取周日開始日期和周日結束日期。

我在下面嘗試通過自我編碼將“周開始日期”作為“星期一”，“周結束日期”作為“星期日”。

$cdate = date("Y-m-d");
$week =  date('W', strtotime($cdate));
$year =  date('Y', strtotime($cdate));      
$firstdayofweek = date("Y-m-d", strtotime("{$year}-W{$week}+1"));
$lastdayofweek = date("Y-m-d", strtotime("{$year}-W{$week}-7"));

謝謝，Vasanth

Answer 1

這是一個使用DateTime的解決方案，它比date和strtotime更好一些：)：

$today = new \DateTime();
$currentWeekDay = $today->format('w'); // Weekday as a number (0 = Sunday, 6 = Saturday)

$firstdayofweek = clone $today;
$lastdayofweek  = clone $today;

if ($currentWeekDay !== '0') {
    $firstdayofweek->modify('last sunday');
}

if ($currentWeekDay !== '6') {
    $lastdayofweek->modify('next saturday');
}

echo $firstdayofweek->format('Y-m-d').PHP_EOL;
echo $lastdayofweek->format('Y-m-d').PHP_EOL;

Answer 2

更改您的本地配置：

setlocale('LC_TIME', 'fr_FR.utf8');

根據您所在的地方更改“ fr_FR.utf8”。

Answer 3

我如下更改了代碼。 此代碼正確嗎？ 但這對我有用。

$cdate = date("Y-m-d");
$week =  date('W', strtotime($cdate));
$year =  date('Y', strtotime($cdate));      
echo "<br>".$firstdayofweek = date("Y-m-d", strtotime("{$year}-W{$week}-0"));
echo "<br>".$lastdayofweek = date("Y-m-d", strtotime("{$year}-W{$week}-6"));