[英]NSDate get next occurring weekday that is in the future
解決我的問題的邏輯是滿口的,我已經想出了一個解決方案。 我的解決方案發布在下面。 我正在尋找是否有人可以提出更有效/更簡單的解決方案。
該方法應該返回給定日期的下一個未來(從現在開始)發生的日期。 在輸入日期和輸出日期之間應保留時間。
對於所有示例,今天是2015年5月8日(星期五)下午4:00:所有投入和產出均在2015年:
+---------------------------+---------------------------+
| Input | Output |
+---------------------------+---------------------------+
| Tuesday April 7, 3:00 PM | Monday May 11, 3:00 PM |
| Thursday May 7, 3:00 PM | Monday May 11, 3:00 PM |
| Thursday May 7, 5:00 PM | Friday May 8, 5:00 PM |
| Tuesday May 12, 3:00 PM | Wednesday May 13, 3:00 PM |
| Saturday June 20, 3:00 PM | Monday June 22, 3:00 PM |
+---------------------------+---------------------------+
這是邏輯的一些偽代碼:
do {
date += 1 day;
} while(date.isWeekend || date.isInThePast)
這是我想出的解決方案,避免使用循環來牢記效率:
- (NSDate *)nextWeekDayInFuture {
NSDate *now = [NSDate date];
NSDate *nextWeekDaydate;
NSCalendar *calendar = [NSCalendar currentCalendar];
nextWeekDaydate = [self dateByAddingDays:1]; // custom method, adds 1 day
if ([nextWeekDaydate isLessThan:now]) {
NSDateComponents *nowComponents = [calendar components:(NSCalendarUnitYear | NSCalendarUnitMonth | NSCalendarUnitDay) fromDate:now];
NSDateComponents *dateComponents = [calendar components:(NSCalendarUnitHour | NSCalendarUnitMinute | NSCalendarUnitSecond) fromDate:nextWeekDaydate];
[nowComponents setHour:dateComponents.hour];
[nowComponents setMinute:dateComponents.minute];
[nowComponents setSecond:dateComponents.second];
nextWeekDaydate = [calendar dateFromComponents:nowComponents];
if ([nextWeekDaydate isLessThan:now]) {
nextWeekDaydate = [nextWeekDaydate dateByAddingDays:1];
}
}
NSDateComponents *components = [calendar components:NSCalendarUnitWeekday fromDate:nextWeekDaydate];
if (components.weekday == Saturday) {
nextWeekDaydate = [nextWeekDaydate dateByAddingDays:2];
} else if (components.weekday == Sunday) {
nextWeekDaydate = [nextWeekDaydate dateByAddingDays:1];
}
return nextWeekDaydate;
}
發布解決方案之前,請使用上方的輸入/輸出表測試您的邏輯。
沒有理由不將邏輯置於循環中,因為至多它會循環兩次(如果當前日期是星期六)。
如果當前一天是周末,這是解決問題的解決方案: 如何使用NSDate從今天開始查找工作日?
- (NSInteger)isWeekend:(NSDate*)inDate
{
NSCalendar* cal = [NSCalendar currentCalendar];
NSDateComponents* comp = [cal components:kCFCalendarUnitWeekday fromDate:inDate];
return [comp weekday];
}
然后,我們可以調用此方法,檢查返回的NSInteger以查看它是坐着還是曬太陽,然后再次運行它:
NSDate *now = [NSDate date];
now = [now dateByAddingTimeInterval:60*60*24]; // Add 1 day's worth.
NSInteger curDay = [self isWeekend:now];
while ((curDay == 6) || (curDay == 1)) // Sat or Sund.
{
now = [now dateByAddingTimeInterval:60*60*24]; // Add 1 day's worth.
curDay = [self isWeekend:now];
}
如果您確實想刪除該循環,則可以檢查它是否是星期六並增加了2天的價值,或者如果是星期日並又增加了1天的價值。
NSDate *now = [NSDate date];
now = [now dateByAddingTimeInterval:60*60*24]; // Add 1 day's worth.
NSInteger curDay = [self isWeekend:now];
if (curDay == 6) // Sat
{
now = [now dateByAddingTimeInterval:60*60*24*2]; // Add 2 day's worth.
}
else if (curDay == 1) // Sun
{
now = [now dateByAddingTimeInterval:60*60*24]; // Add 1 day's worth.
}
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