MySQL從多個表中復制SELECT中的數據

Question

我有6張桌子，根據以下結構 我正在使用的查詢

SELECT 
    campaigns.idCampaign,

    users.idUser AS idUser,
    users.identification AS userIdentification,
    users.name AS userName,
    campaign_users.commission AS userCommission,
    campaign_files.idFile AS idFile,
    campaign_files.name AS fileName,
    clients.identification AS clientIdentification,
    suppliers.identification AS supplierIdentification
FROM
    campaigns
    LEFT JOIN campaign_users ON( campaigns.idCampaign = campaign_users.idCampaign)
    LEFT JOIN users ON( users.idUser = campaign_users.idUser )
    LEFT JOIN clients USING( idClient )
    LEFT JOIN suppliers ON ( suppliers.idSupplier = campaigns.idSupplier )
    LEFT JOIN campaign_files ON( campaigns.idCampaign = campaign_files.idCampaign)

這導致在重復的廣告活動，根據文件數campaign_files或用戶campaign_users （這是更大）。

這是結果，因為您可以看到idCampaign相同但多次，我想在單個對象中這樣做，就像這樣

{

    idCampaign: 4,
    users: [
        {
            idUser: 1,
            userName: 'ADMIN' 
        },
        {
            idUser: 2,
            userName: 'Serena Huel'
        }
    ],
    files: [
        {
            idFile: 23,
            fileName: 'dshds9agds86das8gads8g5dsa.hal'
        },
        {
            idFile: 49,
            fileName: 'dshds9agds86das8gads8g5dsa.hal'
        }
        {
            idFile: 84,
            fileName: 'dshds9agds86das8gads8g5dsa.hal'
        },
        {
            idFile: 99,
            fileName: 'dshds9agds86das8gads8g5dsa.hal'
        }
    ],
    clientIdentification: "dolore",
    ...
}

我已經添加了輸出作為示例，但是它可以是PHP對象，數組等。

Answer 1

可悲的是，這不是MySQL的工作方式。 您可以執行GROUP BY ，例如GROUP_CONCAT ，但這將使您擁有字符串而不是數組。 那么為什么不將其轉換為PHP中的通緝對象呢？

假設查詢可以返回多個campaignId ，則可以這樣進行

$campaigns = array();

while ($row = /* fetch row */) {
    if (!isSet($campaigns[ $row['campaignId'] ])) {
        //new campaignId
        $campaigns[ $row['campaignId'] ] = array(
            'users' => array(),
            'files' => array(),
            'clientIdentification' => $row['clientIdentification']
        );
    }

    if (!isSet($campaigns[ $row['campaignId'] ]['users'][ $row['idUser'] ])) {
        //new user
        $campaigns[ $row['campaignId'] ]['users'][ $row['idUser'] ] = $row['userName'];
    }

    $campaigns[ $row['campaignId'] ]['files'][] = array(
        'idFile' => $row['idFile'],
        'fileName' => $row['fileName']
    );
}

這將為您提供一個數組$campaigns ，幾乎是您想要的。 使用id作為密鑰保存用戶是一種簡單的方法，不會有任何重復的用戶。 現在要獲得預期的對象，您可以執行以下操作

foreach ($campaigns as $c) {
    $expectedObj = array(
        'idCampaign' => $c['idCampaign'],
        'users' => array(),
        'files' => $c['files'],
        'clientIdentification' => $c['clientIdentification']
    );
    foreach ($c['users'] as $idUser => $userName) {
        $expectedObj['users'][] = array(
            'idUser' => $idUser,
            'userName' => $userName
        );
    }
    // use $expectedObj
}