AngularJS拒絕的承諾沒有為$ q.all（）調用onRejection

Question

所以我有這段代碼：

        var deferred = $q.defer();
        var promises = [];

        angular.forEach($scope.devices, function(device){
            var promise = memberService.InsertDevice(memberId, device).then(function (data) {
                //device inserted
            }, function (rejectData) {
                if (rejectData.Error == "Cannot insert record since it already exists") {
                    alert("The number " + device.PhoneNumber + " already exists. Try with a different number.");
                }
            });

            promises.push(promise);
        });

        $q.all(promises).then(function (data) {
            //perform something on Success
        }, function (data) {
           //perform something on rejection
           //THIS NEVER GETS CALLED EVEN IF I GET THE ALERT FROM THE TOP
        });

看看最后的評論。 出於某種原因，即使我得到警報（這意味着其中一個呼叫出現問題），也永遠不會調用整體拒絕。

Answer 1

承諾為您提供了在失敗時“恢復”的機會，因此您必須在錯誤句柄中返回拒絕，以使$q.all知道它確實失敗了。 以下代碼中唯一的增量是return $q.reject(rejectData);

    var deferred = $q.defer();
    var promises = [];

    angular.forEach($scope.devices, function(device){
        var promise = memberService.InsertDevice(memberId, device).then(function (data) {
            //device inserted
        }, function (rejectData) {
            if (rejectData.Error == "Cannot insert record since it already exists") {
                alert("The number " + device.PhoneNumber + " already exists. Try with a different number.");
            }
               return $q.reject(rejectData);
        });

        promises.push(promise);
    });

    $q.all(promises).then(function (data) {
        //perform something on Success
    }, function (data) {
       //perform something on rejection
       //THIS NEVER GETS CALLED EVEN IF I GET THE ALERT FROM THE TOP
    });