[英]In Swift and sprite kit how to detect swiped sprites?
我在屏幕上移動精靈。 現在,我確實抓住了觸摸,如果觸摸了精靈,則將其刪除。 但是我想把它擦掉。 含義-我在其中滑動(任何方向),並且如果它是正確的精靈(檢查名稱),則將其刪除。
我確實有一個觸摸代碼,但是我不認為需要在此處粘貼它,這是非常標准的,並且滑動代碼肯定會有所不同。
有什么建議么? 謝謝!
嘗試這個:
override func touchesMoved(touches: Set<NSObject>, withEvent event: UIEvent)
{
let touch = touches.first as! UITouch
let location = touch.locationInNode(self)
if sprite.frame.contains(location)
{
//remove sprite here
}
}
另外,如果您希望將其輕輕一去,也可以添加以下內容:
override func touchesBegan(touches: Set<NSObject>, withEvent event: UIEvent)
{
let touch = touches.first as! UITouch
let location = touch.locationInNode(self)
if sprite.frame.contains(location)
{
//remove sprite here
}
}
您可以使用UISwipeGestureRecognizer
並獲取開始觸摸的位置。 之后,您可以檢查哪個節點在該位置。
像那樣:
override func didMoveToView(view: SKView) {
//create Swipe gesturerecognizer
var swipe = UISwipeGestureRecognizer()
//set Direction to Left
swipe.direction = .Left
//Call method "swipe" if swipe is done
swipe.addTarget(self, action: "swipe:")
self.view!.addGestureRecognizer(swipe)
}
func swipe(sender: UISwipeGestureRecognizer){
//get amount of touches in swipe
var touches = sender.numberOfTouches()
//loop through touches
for touch in 0..<touches{
var location = sender.locationOfTouch(touch, inView: self.view)
//Get the node at the location of the touch
var swipedNode = self.nodeAtPoint(location)
}
}
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