jQuery如果選中了一個復選框，則根據值禁用其他特定的復選框

Question

我需要的是

<div id="employeedetails-relation" class="check"><div class="checkbox">    <label><input type="checkbox" name="Employeedetails[relation][]" value="1"> Father</label></div>
<div class="checkbox"><label><input type="checkbox" name="Employeedetails[relation][]" value="2"> Mother</label></div>
<div class="checkbox"><label><input type="checkbox" name="Employeedetails[relation][]" value="3"> Spouse</label></div>
<div class="checkbox"><label><input type="checkbox" name="Employeedetails[relation][]" value="4"> Child1</label></div>
<div class="checkbox"><label><input type="checkbox" name="Employeedetails[relation][]" value="5"> Child2</label></div>
<div class="checkbox"><label><input type="checkbox" name="Employeedetails[relation][]" value="6"> Father-in-law</label></div>
<div class="checkbox"><label><input type="checkbox" name="Employeedetails[relation][]" value="7"> Mother-in-law</label></div></div>

在這里，如果我檢查值1 或 2 ，則必須禁用值6 和 7復選框。 同樣，如果我檢查值6 或 7 ，則必須禁用復選框值1 和 2 。

假設如果我先檢查值3，然后再檢查值1或2，則必須再次禁用值6和7。

如果我未選中值1和值2，則必須再次禁用值6和7，或者

我的代碼：

$(\'input[type="checkbox"]\').click(function(){

        if (this.checked && this.value === "1") {
        $(\'#employeedetails-relation input[value="6"\').prop(\'disabled\', \'true\');
        $(\'#employeedetails-relation input[value="7"\').prop(\'disabled\', \'true\');
        } 
        elseif (!this.checked && this.value === "1")
        {
        $(\'#employeedetails-relation input[value="6"\').prop(\'disabled\', \'false\');
        $(\'#employeedetails-relation input[value="7"\').prop(\'disabled\', \'false\');
        }

Answer 1

嘗試這個：

$(document).ready(function() {
    $('#employeedetails-relation').on('change', ':checkbox', function() {
        var value = parseInt($(this).val());

        var checkedEl = [];
        $(':checkbox:checked').each(function() {
            checkedEl.push(parseInt($(this).val()));
        });

        $('#employeedetails-relation :checkbox').prop('disabled', false);

        if ($.inArray(1, checkedEl) > -1 || $.inArray(2, checkedEl) > -1) {
            $(':checkbox[value=6]').prop('disabled', true);
            $(':checkbox[value=7]').prop('disabled', true);
        } else if ($.inArray(6, checkedEl) > -1 || $.inArray(7, checkedEl) > -1) {

            $(':checkbox[value=1]').prop('disabled', true);
            $(':checkbox[value=2]').prop('disabled', true);
        }

    });
});

檢查演示： https : //jsfiddle.net/tusharj/0hoh109k/1/

Answer 2

您的JavaScript代碼中有多個錯誤。 刪除jquery選擇器中的反斜杠，如下所示：

$('input[type="checkbox"]')

您還忘記了選擇器中的尾括號：

$('#employeedetails-relation input[value="6"]')

elseif在javascript中不存在，請將其替換為：

else if

在這里您可以找到代碼的工作示例http://jsfiddle.net/klickagent/up59vsdg/1/ 。

Answer 3

您可以為1,2或6,7設置不同的單擊處理程序，然后檢查是否選中了其中的任何一個，然后設置Disabled屬性

 var $checks12 = $('#employeedetails-relation').find('input[value="1"], input[value="2"]').click(function() { $checks67.prop('disabled', $checks12.is(':checked')); }); var $checks67 = $('#employeedetails-relation').find('input[value="6"], input[value="7"]').click(function() { $checks12.prop('disabled', $checks67.is(':checked')); }); 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script> <div id="employeedetails-relation" class="check"> <div class="checkbox"><label><input type="checkbox" name="Employeedetails[relation][]" value="1"/> Father</label></div> <div class="checkbox"><label><input type="checkbox" name="Employeedetails[relation][]" value="2"/> Mother</label></div> <div class="checkbox"><label><input type="checkbox" name="Employeedetails[relation][]" value="3"/> Spouse</label></div> <div class="checkbox"><label><input type="checkbox" name="Employeedetails[relation][]" value="4"/> Child1</label></div> <div class="checkbox"><label><input type="checkbox" name="Employeedetails[relation][]" value="5"/> Child2</label></div> <div class="checkbox"><label><input type="checkbox" name="Employeedetails[relation][]" value="6"/> Father-in-law</label></div> <div class="checkbox"><label><input type="checkbox" name="Employeedetails[relation][]" value="7"/> Mother-in-law</label></div> </div> 

Answer 4

完美且經過測試的解決方案...只需復制，粘貼和檢查

  <!DOCTYPE html>

<html>
<head>
   <script src="//code.jquery.com/jquery-1.11.3.min.js"></script>
    <script>
    $(document).ready(function(){
      $('input[type="checkbox"]').click(function(){
      if($(this).val()==1 || $(this).val()==2 ){
      $('#checkbox6').attr('disabled','true');    
       $('#checkbox7').attr('disabled','true');    
      }
      })  
    // var check= document.getElementsByName('Employeedetails[relation][]');

   //  alert(check.val);
    });
    </script>
    <meta charset="windows-1252">
    <title></title>
</head>
<body>
    <?php
    // put your code here
    ?>
        <div id="employeedetails-relation" class="check"><div class="checkbox">    <label><input id="checkbox1" type="checkbox" name="Employeedetails[relation][]" value="1"> Father</label></div>

<div class="checkbox"><label><input id="checkbox2" type="checkbox" name="Employeedetails[relation][]" value="2"> Mother</label></div>
<div class="checkbox"><label><input id="checkbox3" type="checkbox" name="Employeedetails[relation][]" value="3"> Spouse</label></div>
<div class="checkbox"><label><input id="checkbox4" type="checkbox" name="Employeedetails[relation][]" value="4"> Child1</label></div>
<div class="checkbox"><label><input  id="checkbox5" type="checkbox" name="Employeedetails[relation][]" value="5"> Child2</label></div>
<div class="checkbox"><label><input   id="checkbox6" type="checkbox" name="Employeedetails[relation][]" value="6"> Father-in-law</label></div>
<div class="checkbox"><label><input id="checkbox7"  type="checkbox" name="Employeedetails[relation][]" value="7"> Mother-in-law</label></div>   </div>
      </body>
</html>