[英]zip creation error in java
我正在使用ZipOutputStream,FileOutputStream和FileInputStream。
首先,我創建了一個包含一個文件的文件夾。 它創建成功。 然后,我嘗試創建zip文件。 動態地,它第一次正確創建文件,但是第二次,第三次打開文件時出錯。
錯誤:zip [path /././ file.zip]無法打開該進程無法訪問該文件,因為該文件正在被另一個進程使用。 我在Java中創建了以下代碼,
我的代碼:
demopath+="/myzip"+po.getPoid();
createDir(demopath);
createFileForFamilies("My content", demopath+"/file");
this.zipDirectory(new File(demopath), demopath+".zip");
我的文件創建器功能:
public String createFileForFamilies(String content, String path) {
FileOutputStream fop = null;
File file;
try {
file = new File(path);
fop = new FileOutputStream(file);
// if file doesnt exists, then create it
if (!file.exists()) {
file.createNewFile();
}
// get the content in bytes
byte[] contentInBytes = content.getBytes();
fop.write(contentInBytes);
fop.flush();
fop.close();
return ("Done");
} catch (IOException e) {
System.err.println(e);
return ("Done");
} finally {
try {
if (fop != null) {
fop.close();
}
} catch (IOException e) {
System.err.println(e);
return ("Abort");
}
}
}
我的Zip創建功能:
public void zipDirectory(File dir, String zipDirName) {
try {
populateFilesList(dir);
//now zip files one by one
//create ZipOutputStream to write to the zip file
FileOutputStream fos = new FileOutputStream(zipDirName);
ZipOutputStream zos = new ZipOutputStream(fos);
for (String filePath : filesListInDir) {
System.out.println("Zipping " + filePath);
//for ZipEntry we need to keep only relative file path, so we used substring on absolute path
ZipEntry ze = new ZipEntry(filePath.substring(dir.getAbsolutePath().length() + 1, filePath.length()));
zos.putNextEntry(ze);
//read the file and write to ZipOutputStream
FileInputStream fis = new FileInputStream(filePath);
byte[] buffer = new byte[1024];
int len;
while ((len = fis.read(buffer)) > 0) {
zos.write(buffer, 0, len);
}
zos.closeEntry();
fis.close();
}
zos.close();
fos.close();
} catch (IOException e) {
e.printStackTrace();
}
}
謝謝鮑里斯...
這是一個解決方案:
Map<String, String> env = new HashMap<>();
env.put("create", "true");
// locate file system by using the syntax
// defined in java.net.JarURLConnection
URI uri = URI.create("jar:file:/"+zipPath+".zip");
try (FileSystem zipfs = FileSystems.newFileSystem(uri, env)) {
java.nio.file.Path externalTxtFile;
java.nio.file.Path pathInZipfile ;
externalTxtFile = Paths.get(gamesPath);
pathInZipfile = zipfs.getPath("/file.txt");
Files.copy(externalTxtFile, pathInZipfile,
StandardCopyOption.REPLACE_EXISTING);
}
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