python命令字典問題

Question

如果我有一個CSV文件，該文件的每一行都有一個字典值（列為[“ Location”]，[“ MovieDate”]，[“ Formatted_Address”]，[“ Lat”]，[“ Lng”]），我如果我想按Location分組並附加在共享相同Location值的所有MovieDate值上，請告訴我使用OrderDict。

數據前：

Location,MovieDate,Formatted_Address,Lat,Lng
    "Edgebrook Park, Chicago ",Jun-7 A League of Their Own,"Edgebrook Park, 6525 North Hiawatha Avenue, Chicago, IL 60646, USA",41.9998876,-87.7627672
    "Edgebrook Park, Chicago ","Jun-9 It's a Mad, Mad, Mad, Mad World","Edgebrook Park, 6525 North Hiawatha Avenue, Chicago, IL 60646, USA",41.9998876,-87.7627672

對於具有相同位置的每一行（如本示例中的^），我要進行這樣的輸出，以便沒有重復的位置。

 "Edgebrook Park, Chicago ","Jun-7 A League of Their Own Jun-9 It's a Mad, Mad, Mad, Mad World","Edgebrook Park, 6525 North Hiawatha Avenue, Chicago, IL 60646, USA",41.9998876,-87.7627672

我的使用ordereddict執行此操作的代碼有什么問題？

from collections import OrderedDict

od = OrderedDict()
import csv
with open("MovieDictFormatted.csv") as f,open("MoviesCombined.csv" ,"w") as out:
    r = csv.reader(f)
    wr = csv.writer(out)
    header = next(r)
    for row in r:
        loc,rest = row[0], row[1]
        od.setdefault(loc, []).append(rest)
    wr.writerow(header)
    for loc,vals in od.items():
        wr.writerow([loc]+vals)

我最終得到的是這樣的：

['Edgebrook Park, Chicago ', 'Jun-7 A League of Their Own']
['Gage Park, Chicago ', "Jun-9 It's a Mad, Mad, Mad, Mad World"]
['Jefferson Memorial Park, Chicago ', 'Jun-12 Monsters University ', 'Jul-11 Frozen ', 'Aug-8 The Blues Brothers ']
['Commercial Club Playground, Chicago ', 'Jun-12 Despicable Me 2']

問題是在這種情況下我沒有讓其他列顯示，我該怎么做呢？ 我還希望將MovieDate值設置為一個長字符串，例如： 'Jun-12 Monsters University Jul-11 Frozen Aug-8 The Blues Brothers '而不是：

'Jun-12 Monsters University ', 'Jul-11 Frozen ', 'Aug-8 The Blues Brothers '

謝謝大家，謝謝。 我是python noob。

不幸的是row[0], row[1]將row[0], row[1]更改為row[0], row[1:]並沒有得到我想要的東西。我只想在第二列（MovieDate）中添加值，而不是復制其他所有列，例如：

['Jefferson Memorial Park, Chicago ', ['Jun-12 Monsters University ', 'Jefferson Memorial Park, 4822 North Long Avenue, Chicago, IL 60630, USA', '41.76083920000001', '-87.6294353'], ['Jul-11 Frozen ', 'Jefferson Memorial Park, 4822 North Long Avenue, Chicago, IL 60630, USA', '41.76083920000001', '-87.6294353'], ['Aug-8 The Blues Brothers ', 'Jefferson Memorial Park, 4822 North Long Avenue, Chicago, IL 60630, USA', '41.76083920000001', '-87.6294353']]

Answer 1

您只需要進行一些更改，就需要加入經緯度，以刪除重復的經緯度，我們還需要將其用作鍵：

with open("data.csv") as f,open("new.csv" ,"w") as out:
    r = csv.reader(f)
    wr= csv.writer(out)
    header = next(r)
    for row in r:
        od.setdefault((row[0], row[-2], row[-1]), []).append(" ".join(row[1:-2]))
    wr.writerow(header)
    for loc,vals in od.items():
        wr.writerow([loc[0]] + vals+list(loc[1:]))

輸出：

Location,MovieDate,Formatted_Address,Lat,Lng
"Edgebrook Park, Chicago ","Jun-7 A League of Their Own Edgebrook Park, 6525 North Hiawatha Avenue, Chicago, IL 60646, USA","Jun-9 It's a Mad, Mad, Mad, Mad World Edgebrook Park, 6525 North Hiawatha Avenue, Chicago, IL 60646, USA",41.9998876,-87.7627672

A League of Their Own因為它出現在瘋狂，瘋狂的行， row[1:-2] ，不包括緯度，經度和位置，我們將緯度和經度存儲在關鍵元組中，以避免重復寫於每行的末尾。

使用名稱和拆包可能會使跟蹤變得更容易一些：

with open("data.csv") as f, open("new.csv", "w") as out:
    r = csv.reader(f)
    wr = csv.writer(out)
    header = next(r)
    for row in r:
        loc, mov, form, lat, long = row
        od.setdefault((loc, lat, long), []).append("{} {}".format(mov, form))
    wr.writerow(header)
    for loc, vals in od.items():
        wr.writerow([loc[0]] + vals + list(loc[1:]))

使用csv.Dictwriter保留五列：

od = OrderedDict()
import csv

with open("data.csv") as f, open("new.csv", "w") as out:
    r = csv.DictReader(f,fieldnames=['Location', 'MovieDate', 'Formatted_Address', 'Lat', 'Lng'])
    wr = csv.DictWriter(out, fieldnames=r.fieldnames)
    for row in r:
        od.setdefault(row["Location"], dict(Location=row["Location"], Lat=row["Lat"], Lng=row["Lng"],
                                        MovieDate=[], Formatted_Address=row["Formatted_Address"]))

        od[row["Location"]]["MovieDate"].append(row["MovieDate"])
    for loc, vals in od.items():
        od[loc]["MovieDate"]= ", ".join(od[loc]["MovieDate"])
        wr.writerow(vals)

＃輸出：

"Edgebrook Park, Chicago ","Jun-7 A League of Their Own, Jun-9 It's a Mad, Mad, Mad, Mad World","Edgebrook Park, 6525 North Hiawatha Avenue, Chicago, IL 60646, USA",41.9998876,-87.7627672

因此，這五列保持不變，我們將"MovieDate"到單個字符串中，並且Formatted_Address=form始終是唯一的，因此我們不需要對其進行更新。

事實證明，要匹配您想要做的所有事情，就是串聯MovieDate's並刪除Location，Lat，Lng和'Formatted_Address'重復條目。

Answer 2

讓我們嘗試改變

od.setdefault(loc, []).append(rest) 

至

od[loc] = ' '.join([od.get(loc, ''), ' 'join(rest)])

然后保持原樣：

wr.writerow([loc]+vals)

Answer 3

假設位置是該行的第一項：

dict = {}
for line in f:
    if line[0] not in dict:
        dict[line[0]] = []
    dict[line[0]].append(line[1:])

對於每個位置，您都擁有整個行的其余部分

for key, value in dict.iteritems():
    out.write(key + value)