傳遞表並將表返回到存儲過程或函數？

Question

我想將一個表傳遞給UDF或存儲過程，然后讓它處理數據並從我傳遞給它的表中返回靈敏度，特異性和95％的上/下置信區間（每個）。

基本上，我需要從一個表中計算並返回六個值。

我必須這樣做很多次，所以自動化會很棒，但是我還沒有創建UDF或SP。 我已經閱讀了它們（stackoverflow和其他地方，但仍對如何進行操作有所了解。

我創建了SQL部分來計算感興趣的參數，但是我對如何將表傳遞給表以及將表取回感到迷惑不解。

DECLARE @R_MODS TABLE(
  SUBJECTID varchar(max),
  ResultCall varchar(max)
)

INSERT INTO @R_MODS VALUES ('11-0001','TP');
INSERT INTO @R_MODS VALUES ('11-0002','TP');
INSERT INTO @R_MODS VALUES ('11-0003','TP');
INSERT INTO @R_MODS VALUES ('11-0004','TP');
INSERT INTO @R_MODS VALUES ('11-0005','TP');
INSERT INTO @R_MODS VALUES ('11-0006','I');
INSERT INTO @R_MODS VALUES ('11-0007','TP');
INSERT INTO @R_MODS VALUES ('11-0008','TP');
INSERT INTO @R_MODS VALUES ('11-0009','I');
INSERT INTO @R_MODS VALUES ('11-0010','TP');
INSERT INTO @R_MODS VALUES ('11-0011','TP');
INSERT INTO @R_MODS VALUES ('11-0012','TN');
INSERT INTO @R_MODS VALUES ('11-0013','TP');
INSERT INTO @R_MODS VALUES ('11-0014','I');
INSERT INTO @R_MODS VALUES ('11-0015','TP');
INSERT INTO @R_MODS VALUES ('11-0016','TP');
INSERT INTO @R_MODS VALUES ('11-0017','TN');
INSERT INTO @R_MODS VALUES ('11-0018','TP');
INSERT INTO @R_MODS VALUES ('11-0019','FP');
INSERT INTO @R_MODS VALUES ('11-0020','FP');

DECLARE @TP float, @TN float, @FP float, @FN float, @SEN float, @SPE float, @M1 float, 
        @M2 float, @Sen95 float, @SpeL float , @SpeU float, @SenU float, @SenL float

SET @TP = (SELECT COUNT(SUBJECTID) FROM @R_MODS WHERE ResultCall='TP')
SET @TN = (SELECT COUNT(SUBJECTID) FROM @R_MODS WHERE ResultCall='TN')
SET @FP = (SELECT COUNT(SUBJECTID) FROM @R_MODS WHERE ResultCall='FP')
SET @FN = (SELECT COUNT(SUBJECTID) FROM @R_MODS WHERE ResultCall='FN')

SET @SEN = @TP/(@TP + @FN)
SET @M1 = @TP + @FN 

SET @SPE = @TN/(@TN + @FP)
SET @M2 =  @FP + @TN 

SET @SenL = ( 2*@M1*@SEN + POWER(1.96,2) - 1 - 1.96 * SQRT(POWER(1.96,2) 
    - 2 -(1/@M1)+ 4*@SEN *(@M1*(1-@SEN) + 1)))/(2*(@M1+POWER(1.96,2)))
SET @SenU = ( 2*@M1*@SEN + POWER(1.96,2) + 1 + 1.96 * SQRT(POWER(1.96,2) 
    + 2 -(1/@M1)+ 4*@SEN *(@M1*(1-@SEN) - 1)))/(2*(@M1+POWER(1.96,2)))

SET @SpeL = ( 2*@M2*@SPE + POWER(1.96,2) - 1 - 1.96 * SQRT(POWER(1.96,2) 
    - 2 -(1/@M2)+ 4*@SPE *(@M2*(1-@SPE) + 1)))/(2*(@M2+POWER(1.96,2)))
SET @SpeU = ( 2*@M2*@SPE + POWER(1.96,2) + 1 + 1.96 * SQRT(POWER(1.96,2) 
    + 2 -(1/@M2)+ 4*@SPE *(@M2*(1-@SPE) - 1)))/(2*(@M2+POWER(1.96,2)))

SELECT @SEN, @SenL, @SenU, 1-@SPE, 1-@SPEL, 1-@SpeU     

Answer 1

由於您的代碼僅對數據進行計算（即沒有副作用或表更新），並且不與表耦合，因此您可以創建一個表值函數來進行這些計算-該函數可以將輸入表（ R_MODS ）作為表類型 ，還返回輸出表（ Sen等）。

這是SqlFiddle示例 。

詳細：

您需要為輸入創建表類型，例如

CREATE TYPE R_MODS_TYPE AS TABLE(
  SUBJECTID varchar(max),
  ResultCall varchar(max)
);

並這樣定義函數：

CREATE FUNCTION dbo.DoCalcs(@TheRMods R_MODS_TYPE READONLY)
RETURNS @Result TABLE
(
    [SEN] DECIMAL(10,4), 
    [SenL] DECIMAL(10,4), 
    [SenU] DECIMAL(10,4),  
    [1-SPE] DECIMAL(10,4), 
    [1-SPEL] DECIMAL(10,4), 
    [1-SpeU] DECIMAL(10,4)
)
AS
BEGIN
    DECLARE @TP float, @TN float, @FP float, @FN float, @SEN float, @SPE float, 
            @M1 float, @M2 float, @Sen95 float, @SpeL float , @SpeU float, 
            @SenU float, @SenL float;

    SET @TP = (SELECT COUNT(SUBJECTID) FROM @TheRMods WHERE ResultCall='TP')
    SET @TN = (SELECT COUNT(SUBJECTID) FROM @TheRMods WHERE ResultCall='TN')
    SET @FP = (SELECT COUNT(SUBJECTID) FROM @TheRMods WHERE ResultCall='FP')
    SET @FN = (SELECT COUNT(SUBJECTID) FROM @TheRMods WHERE ResultCall='FN')

    SET @SEN = @TP/(@TP + @FN)
    SET @M1 = @TP + @FN 

    SET @SPE = @TN/(@TN + @FP)
    SET @M2 =  @FP + @TN 

    SET @SenL = ( 2*@M1*@SEN + POWER(1.96,2) - 1 - 1.96 * SQRT(POWER(1.96,2) 
          - 2 -(1/@M1)+ 4*@SEN *(@M1*(1-@SEN) + 1)))/(2*(@M1+POWER(1.96,2)))
    SET @SenU = ( 2*@M1*@SEN + POWER(1.96,2) + 1 + 1.96 * SQRT(POWER(1.96,2) 
          + 2 -(1/@M1)+ 4*@SEN *(@M1*(1-@SEN) - 1)))/(2*(@M1+POWER(1.96,2)))

    SET @SpeL = ( 2*@M2*@SPE + POWER(1.96,2) - 1 - 1.96 * SQRT(POWER(1.96,2) 
      - 2 -(1/@M2)+ 4*@SPE *(@M2*(1-@SPE) + 1)))/(2*(@M2+POWER(1.96,2)))
    SET @SpeU = ( 2*@M2*@SPE + POWER(1.96,2) + 1 + 1.96 * SQRT(POWER(1.96,2) 
      + 2 -(1/@M2)+ 4*@SPE *(@M2*(1-@SPE) - 1)))/(2*(@M2+POWER(1.96,2)))

    INSERT INTO @Result ([SEN], [SenL], [SenU], [1-SPE], [1-SPEL], [1-SpeU])
        SELECT @SEN, @SenL, @SenU, 1-@SPE, 1-@SPEL, 1-@SpeU;
    RETURN;
END

然后，您通過聲明表類型的實例，填充表實例並將其傳遞給函數來調用表函數：

DECLARE @TestData R_MODS_TYPE;

INSERT INTO @TestData VALUES ('11-0001','TP'),
('11-0002','TP'),
('11-0003','TP'),
('11-0004','TP'),
... etc.

SELECT * FROM dbo.DoCalcs(@TestData);

結果：

SEN       SenL     SenU    1-SPE   1-SPEL  1-SpeU
--------- -------- ------- ------- ------- -------
1.0000    0.7166   0.9929  0.5000  0.9081  0.0919

Answer 2

這是使用Stored Procedure另一種方法

您需要輸入參數的用戶定義表數據類型。

CREATE TYPE R_MODS_TBL AS TABLE(
    SUBJECTID VARCHAR(MAX),
    ResultCall VARCHAR(MAX)
)

和存儲過程：

注意變量@TP ， @TN ， @FP和@FN的分配更改，以使用單個SELECT語句而不是四個單獨的SELECT語句。

CREATE PROCEDURE  dbo.YourStoredProcedure(
    @R_MODS R_MODS_TBL READONLY
)
AS

DECLARE 
    @TP FLOAT, @TN FLOAT, @FP FLOAT, @FN FLOAT,
    @SEN FLOAT, @SPE FLOAT, @M1 FLOAT, @M2 FLOAT, @Sen95 FLOAT,
    @SpeL FLOAT, @SpeU FLOAT, @SenU FLOAT, @SenL FLOAT

SELECT
    @TP = COUNT(CASE WHEN ResultCall='TP' THEN SUBJECTID END),
    @TN = COUNT(CASE WHEN ResultCall='TN' THEN SUBJECTID END),
    @FP = COUNT(CASE WHEN ResultCall='FP' THEN SUBJECTID END),
    @FN = COUNT(CASE WHEN ResultCall='FN' THEN SUBJECTID END)
FROM @R_MODS

SET @SEN = @TP/(@TP + @FN)
SET @M1 = @TP + @FN 

SET @SPE = @TN/(@TN + @FP)
SET @M2 =  @FP + @TN 

SET @SenL = (2*@M1*@SEN + POWER(1.96,2) - 1 - 1.96 * SQRT(POWER(1.96,2) - 2 -(1/@M1)+ 4*@SEN *(@M1*(1-@SEN) + 1)))/(2*(@M1+POWER(1.96,2)))
SET @SenU = (2*@M1*@SEN + POWER(1.96,2) + 1 + 1.96 * SQRT(POWER(1.96,2) + 2 -(1/@M1)+ 4*@SEN *(@M1*(1-@SEN) - 1)))/(2*(@M1+POWER(1.96,2)))

SET @SpeL = (2*@M2*@SPE + POWER(1.96,2) - 1 - 1.96 * SQRT(POWER(1.96,2) - 2 -(1/@M2)+ 4*@SPE *(@M2*(1-@SPE) + 1)))/(2*(@M2+POWER(1.96,2)))
SET @SpeU = (2*@M2*@SPE + POWER(1.96,2) + 1 + 1.96 * SQRT(POWER(1.96,2) + 2 -(1/@M2)+ 4*@SPE *(@M2*(1-@SPE) - 1)))/(2*(@M2+POWER(1.96,2)))

SELECT @SEN, @SenL, @SenU, 1-@SPE, 1-@SPEL, 1-@SpeU 

要執行存儲過程，您想填充一個生成的用戶定義表數據類型的實例：

DECLARE @R_MODS R_MODS_TBL

INSERT INTO @R_MODS VALUES ('11-0001','TP');
INSERT INTO @R_MODS VALUES ('11-0002','TP');
INSERT INTO @R_MODS VALUES ('11-0003','TP');
INSERT INTO @R_MODS VALUES ('11-0004','TP');
INSERT INTO @R_MODS VALUES ('11-0005','TP');
INSERT INTO @R_MODS VALUES ('11-0006','I');
INSERT INTO @R_MODS VALUES ('11-0007','TP');
INSERT INTO @R_MODS VALUES ('11-0008','TP');
INSERT INTO @R_MODS VALUES ('11-0009','I');
INSERT INTO @R_MODS VALUES ('11-0010','TP');
INSERT INTO @R_MODS VALUES ('11-0011','TP');
INSERT INTO @R_MODS VALUES ('11-0012','TN');
INSERT INTO @R_MODS VALUES ('11-0013','TP');
INSERT INTO @R_MODS VALUES ('11-0014','I');
INSERT INTO @R_MODS VALUES ('11-0015','TP');
INSERT INTO @R_MODS VALUES ('11-0016','TP');
INSERT INTO @R_MODS VALUES ('11-0017','TN');
INSERT INTO @R_MODS VALUES ('11-0018','TP');
INSERT INTO @R_MODS VALUES ('11-0019','FP');
INSERT INTO @R_MODS VALUES ('11-0020','FP');

EXEC dbo.YourStoredProcedure @R_MODS

SQL小提琴

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注意：

在存儲過程中使用值表作為輸入參數時，需要將參數聲明為READONLY 。 閱讀Mikael Eriksson的答案，以獲得更多信息。