如何檢查最接近的數組值，從變量中減去它，然后重新檢查，每次都回顯

Question

$widgetsRequested = 2467; // Our magic variable - user input


  echo 'Original Number:';
    echo $widgetsRequested;
    echo '<br>';

    $widgetBatches = array("250", "500", "1000", "2000");
        rsort($widgetBatches);
        foreach ($widgetBatches as $key => $val) {
    } // Reverse sort values

    $processWidgetTotal = $widgetBatches; // Pass it on to process

function compareWidgets1($processWidgetTotal, $number) {    // run this once to compare
    sort($processWidgetTotal);
    foreach ($processWidgetTotal as $a) {
        if ($a >= $number) return $a;
    }
    return end($processWidgetTotal); 
}

echo 'Our Closest Matching Batch is: ';
echo $totalRemaining1 = compareWidgets1($processWidgetTotal, $widgetsRequested); // Go through and find the closest match within the widgetBatches array
echo '<br>';

echo 'Left To Allocate: ';
echo $newWidgetTotal1 = $widgetsRequested - $totalRemaining1; // Go through and find the closest match within the widgetBatches array
echo '<br>';

我需要做的是讓用戶輸入（$ widgetsRequested）與compareWidgets1函數（檢查$ widgetBatches數組中最接近的匹配項）進行比較，然后回顯最接近的匹配項，從用戶輸入中扣除它，然后再次循環直到$ widgetsRequested達到0或第一個否定結果（即-5）。

我在想我需要一個dowhile循環嗎？ 但是我無法讓該功能直接位於其中，請幫忙嗎？

Answer 1

這就是我如何解決您的問題：

public $iterations = 0;

private function Widget($userinput)
{
    $this->iterations++;
    $widgetRequested = $userinput;
    $widgetBatches = array("250", "500", "1000", "2000");
    echo "Iteration " . $this->iterations;
    echo "<br/>";

    echo "Widget requested: " . $widgetRequested;
    echo "<br/>";

    $closest = $this->GetClosest($widgetBatches, $widgetRequested);
    echo "Closest: " . $closest;
    echo "<br/>";

    $widgetRemaining = $widgetRequested - $closest;
    echo "Remainder: " . $widgetRemaining;

    echo "<hr/>";
    if($widgetRemaining > 0)
    {
        $this->Widget($widgetRemaining);
    }
    else
    {
        echo "The value is now below or equaling zero: " . $widgetRemaining . "!";
    }
}

//Code is from: http://stackoverflow.com/questions/5464919/php-nearest-value-from-an-array
private function GetClosest(array $array, $value)
{
    $lowest = null;
    foreach($array as $val)
    {
        if($lowest == null || abs($value - $lowest) > abs($val - $value))
        {
            $lowest = $val;
        }
    }

    return $lowest;
}

**注意：這是在我當前的項目中進行的，可能需要對$ this關鍵字進行一些其他更改。*

基本上，我們正在做的是獲取最接近的匹配，並存儲該值。 在那之后，我們用最接近和用戶輸入的結果減去它。 然后，我們執行一個if子句以查看是否小於零。 如果沒有，我們將使用剛剛生成的值再次調用該函數。

輸出：

Iteration 1
Widget requested: 2467
Closest: 2000
Remainder: 467

Iteration 2
Widget requested: 467
Closest: 500
Remainder: -33

The value is now below or equaling zero: -33!